Question

0. 1. A total of 10000 hours was spent inspecting 400,000 lines of code with the result that 6000 potential defects were prevented. Assume that a programmer cost $55/hour.  
1. What is the total cost of preventing 6000 defects?
2. What is the cost of preventing one defect?
   2. Suppose that there had been no inspections and three defects per 1000 lines of code escaped into the shipped product. In order to fix a field defect, it cost $30000 per defect.

1. How many defects per 400,000 lines of code will be escaped?
2. What is the overall cost of fixing field defects (derived/computed in part a)?
3. What is the cost relationship between the overall cost calculated in 3.1 and overall cost calculated in 3.2?

Answer 1

3.1

(b & c)

Python Program:

total_hours = 10000
lines_of_code = 400000
potential_defects = 6000
programmer_cost = 55

total_cost1 = total_hours * programmer_cost
cost_one_defect = total_cost1 // potential_defects
print("total cost of preventing 6000 defects : ", total_cost1)
print("the cost of preventing one defect : ", cost_one_defect)

Output:

3.2

(a & b)

Python Program:

defect_per_1000 = 3
cost_per_defect = 30000
lines_of_code = 400000
total_defects = defect_per_1000 * (lines_of_code // 1000)
total_cost2 = total_defects * cost_per_defect
print("total defects per 400,000 lines of code will be escaped : ", total_defects)
print("the overall cost of fixing field defects : ", total_cost2)

Output:

(c.)

3.1 ====> 6000 defects <--> $550000

3.2 ====> 1200 defects <--> $36000000

The overall cost in 3.1 is 550000 and in 3.2 is 36000000. The 3.1 is too cost-effective as you can see there is a large difference in the overcall cost. I definitely suggest the company have to use 3.1 by fixing the amount of the programmer. And yes you can take half of the 3.2 overall cost amount as a budget to find defects so that you can complete the work in the figure around 3.1 and save money from it.

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