In: Biology
Two autosomal genes control horn color in dragons. Pure-breeding gold-horned dragons were mated to pure-breeding silver-horned dragons. All of the F1 were gold. The F1 were intermated and the F2 generation consisted of 147 gold, 16 silver and 93 bronze.
Conduct a chi-square test to test the appropriate type of
epistasis.
In the chi-square test, what is the expected number of gold-horned
dragons? Round to two decimal places.
Conduct a chi-square test to test the appropriate type of
epistasis.
In the chi-square test, what is the expected number of
silver-horned dragons? Round to two decimal places.
Answer:
As per the information:
Punnett square for this cross can be represented as:
G | g | |
G | GG | Gg |
g | Gg | gg |
F2 generation consists of 147 gold, 16 silver and 93 bronze (Total = 147 + 16 + 93 = 256)
Dominant epistatsis is suggested by 12:3:1 ratio
Recessive epistatsis is suggested by 9:3:4 ratio.
In this case the ratio is 9:6:1 which is similar to 9:4:3, indicating that epistasis is probably occurring between these two genes.
Chi square analysis can be performed as below:
Degree of freedom = Number of categories - 1 = 3 - 1 = 2
Observed Frequency (O) | Expected Frequency € | (O-E) | (O-E)^2/E | |
GG | 147 | 144 | 3 | 0.06 |
Gg | 93 | 96 | -3 | 0.09 |
gg | 16 | 16 | 0 | 0.00 |
Total | 256 | 256 | Chi square (Sum) | 0.16 |
P-value corresponding to chi square value of 0.16 with 2 degree of freedom: P-Value is 0.923116. The result is not significant at p < 0.05. There is sufficient evidence that there is no significant difference in observed frequency as compared to expected frequency based on the epistasis ratio of 9:6:1