In: Statistics and Probability
Question 6 (1 point)
According to a survey of 786 small business participants chosen at random in the Constant Contact Small Biz Council in May of 2013, 431 of the respondents say it is harder to run a small business now than it was 5 years ago. When estimating the population proportion, what is the 90% confidence interval estimating the proportion of businesses who believe it is harder to run a business now than 5 years ago?
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Question 7 (1 point)
A U.S. census bureau pollster noted that in 379 random households surveyed, 218 occupants owned their own home. What is the 99% confidence interval estimate of the proportion of American households who own their own home?
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Question 8 (1 point)
You are watching a nightly news broadcast on CNN and the reporter says that a 90% confidence interval for the proportion of Americans who supported going to war in Iraq was ( 0.4073 , 0.4635 ). You also note that the footnote says this is based on a random sample performed by Gallup with 836 respondents. What is the correct interpretation of this confidence interval?
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Question 9 (1 point)
Based on past data, the Student Recreation Center knew that the proportion of students who prefer exercising outside over exercising in a gym was 0.836. To update their records, the SRC conducted a survey. Out of 85 students surveyed, 71 indicated that they preferred outdoor exercise over exercising in a gym. The 99% confidence interval is ( 0.7317 , 0.9389 ). Which of the following statements is the best conclusion?
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6)
sample proportion, = 0.5483
sample size, n = 786
Standard error, SE = sqrt(pcap * (1 - pcap)/n)
SE = sqrt(0.5483 * (1 - 0.5483)/786) = 0.01775
Given CI level is 90%, hence α = 1 - 0.9 = 0.1
α/2 = 0.1/2 = 0.05, Zc = Z(α/2) = 1.645
CI = (pcap - z*SE, pcap + z*SE)
CI = (0.5483 - 1.645 * 0.01775 , 0.5483 + 1.645 * 0.01775)
CI = (0.5191 , 0.5775)
Option (4)
7)
sample proportion, = 0.5752
sample size, n = 379
Standard error, SE = sqrt(pcap * (1 - pcap)/n)
SE = sqrt(0.5752 * (1 - 0.5752)/379) = 0.02539
Given CI level is 99%, hence α = 1 - 0.99 = 0.01
α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.576
CI = (pcap - z*SE, pcap + z*SE)
CI = (0.5752 - 2.576 * 0.02539 , 0.5752 + 2.576 * 0.02539)
CI = (0.5098 , 0.6406)
option (3)
8)
(3)
We are 90% confident that the proportion of all Americans surveyed who supported going to war in Iraq is between 0.4073 and 0.4635.
9)
We can not claim that the proportion of students who prefer outdoor
exercise differs from 0.836.
Option (2)