In: Civil Engineering
Ans) Given,
Load = 2800 lb
Length = 8 ft
Moisture = 19%
Design Moment = WL2/8
W = Load / length
= 2800 / 8
= 350 lb/ft
M = 350 x 82/ 8
M = 2800 lb-ft or 33600 lb-in
Nominal dimension for 2 x 6 DF-L are,
b = 1.5 in
d = 5.5 in
I = bd3/12
= 178 in4
y = d / 2
Section Modulus(Z) = I / y
= bd2/6
= 1.5 x 5.52/6
31.64 in3
Bending Stress = M / Z
= 33600 / 31.64
= 1061.90 psi
Bending stress value (Fb) for 2 x 6 DF-L = 1350 psi
Allowable stress(F'b) = Fb x Cd x CL x Cr x Cm x Ct x Cf
where , Cd = load duration factor (0.9)
CL = beam stability factor (1)
Cr = repetative member factor (1.15)
Cm = wet service factor (1)
Ct = temperature factor (1)
Cf = size factor (1)
F'b = 1350 x 0.9 x 1.15 x 1 x 1 x 1 x1
= 1397.25 psi > 1062 psi ,
Hence OK
Check deflection :
E = 1700000 psi x Cm x Ct
= 1700000 psi
Deflection = 5 WL4 / (384EI)
= 5 x (350/12) x (8 x 12)4 /(384 x 1700000 x 178)
Deflection = 0.106 in < L/ 240
Hence OK
Check shear stress:
V = WL/2
= 350 x 8 /2
V = 1400 lb
Shear stress = V/bd
= 1400/(1.5 x 5.5)
= 169.70 psi
Allowable shear stress = Fv x Cd x Cm x Ct x Ch
= 180 x 1 x 1 x 1 x1
= 180 psi > 169.7 psi
Hence Ok