The glutamate side chain has a pKa of 4.4. Calculate the percentage of Glu that is...

The glutamate side chain has a pKa of 4.4. Calculate the percentage of Glu that is unprotonated at a pH of 4.7.

Expert Solution

Henderson-Hasselbalch equation can be used to find the percentage of unprotonated Glu at pH 4.7

pH = pK + log [A^-] / [HA]

Given in the question, pH = 4.7 and pK_a = 4.4

Therefore, substituting these values in Henderson Hasselbalch equation,

log [A^-] / [HA] = pH - pK_a

[A^-] / [HA] = 10^(pH-pK_a) = 10^{(4.7 - 4.4)}

[A^-] / [HA] = 10^0.3 = 1.9952

Percentage of [A^-] =

=

= 0.6661 x 100 = 66.61%

Therefore, about 66.61% Glu is unprotonated at pH 4.7

gladiator answered 1 year ago

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