1)
Of 140 adults selected randomly from one town, 35 of them smoke.
Construct a 99%...
1)
Of 140 adults selected randomly from one town, 35 of them smoke.
Construct a 99% confidence interval for the true percentage of all
adults in the town that smoke.
In one town, we are 99% confident that the true percentage of
adults who smoke is between ______% and _______%
2) A survey of 865 voters in one state reveals that 408 favor
approval of an issue before the legislature. Construct the 95%
confidence interval for the true proportion of all voters in the
state who favor approval.
We are 95%confident that the true proportion of those who
favor approval is between _____ and ________
Solutions
Expert Solution
Solution:-
1) we are 99% confident that the true percentage of adults who
smoke is between 15.6% and 34.4%
2) We are 95%confident that the true proportion of those who
favor approval is between 0.438 and 0.505
Of 250 adults selected randomly from one town, 72 of them smoke.
Construct a 95% confidence interval for the true percentage of all
adults in the town that smoke
Of 147 adults selected randomly in one town, it was found that
31 of them smoke. If we were to calculate a 95% confidence interval
for the proportion of people in this town who smoke, what is the
margin of error? Round to 3 decimal places.
of 200 adults randomly selected from one town 43 of them smoke.
find the best point estimate for the proportion of all adults in
town who smoke. for a 95% confidence interval for the true
proportion of all adults in the town who smoke, what is the margin
of error ? round up to three decimal places.
Of 94 adults selected randomly from one town, 62 have health
insurance. Find a 90% confidence interval for the proportion of all
adults in the town who have health insurance.
9) In a sample of 400 people selected randomly from one town, it
is found that 130 of them are Gamecock Fans. At the 0.05
significance level, test the claim that the proportion of all
people in the town who are Gamecock fans is 27%.
A] What type of statistical test can be used
here?
a. Z-test of proportions
c. F
Test
e. Either c2 or λ Test
b. a-Test of
proportions
d. Either T or
F-Test
f. T-Test...
1. Assume that when adults with smartphones are randomly
selected, 56% use them in meetings or classes. If 5 adult
smartphone users are randomly selected, find the probability that
at least 2 of them use their smartphones in
meetings or classes.
2. Assume that when adults with smartphones are randomly
selected, 56% use them in meetings or classes. If 12 adult
smartphone users are randomly selected, find the probability that
fewer than 4 of them use their smartphones in
meetings...
1) assume that when adults with smartphones are randomly
selected, 48% use them in meetings or classes. If 6 adult
smartphone users are randomly selected, find the probability that
at least 3 of them use their smartphones in meetings or classes the
probability is ? 2)
assume that hybridization experiments are conducted with peas
having the property that for offspring, there is a 0.25
probability that a pea has green pods. Assume that the offspring
peas are randomly selected in...
assume that when adults with smart phones are randomly
selected, 54% of them and use them in meetings. If 12 adult
smartphone users are randomly selected, find the probability that
fewer than 4 of them use their smart phones in meetings or
classes.
Assume that when adults with smartphones are randomly selected,
49% of them use them in meetings or classes. If 30 adult smartphone
users are randomly selected, find the probability that exactly 18
of them use their smartphones in meetings or classes
The probability is ____
- Assume that when adults with smartphones are randomly
selected, 65% use them in meetings or classes. If 5 adult
smartphone users are randomly selected, find the probability that
exactly 3 of them use their smartphones in meetings or classes.
- Assume that when adults with smartphones are randomly
selected, 41% use them in meetings or classes. If 20 adult
smartphone users are randomly selected, find the probability that
exactly 13 of them use their smartphones in meetings or
classes....