In: Chemistry
a) A first order reaction is 28.5 % complete in 1908 minutes. Determine the rate constant, k, for the reaction
b) A first order reaction has a of 136.25 minutes. Determine how much time will be required for 39.5% of the original material to decompose.
c) It took 62.43 days for 50% of a substance to decompose. If the reaction follows first order kineticsdetermine the value of the rate constant, k in s-1.
a)
time = 1908 min
rate constant k = 1/t ln (Ao / At)
= 1/ 1908 ln (100 / 100 - 28.5)
rate constant k = 1.76 x 10^-4 min-1
b)
half - life = 136.25 min
rate constant = 0.693 / t1/2
= 0.693 / 136.25
= 5.086 x 10^-3 min-1
rate constant = 1/t ln (Ao / At)
5.086 x 10^-3 = 1/t ln (100 / 100 - 39.5)
t = 98.8 min
time taken = 98.8 min
c)
half - life = 62.43 days = 5393952 sec
rate constant = 0.693 / t1/2
= 0.693 / 5393952
rate constant = 1.28 x 10^-7 s-1