In: Statistics and Probability
Q1. Researchers were interested in determining whether there were any differences in the tendency to procrastinate based on birth order, i.e. first, second, or third child born. Using the data in the table below, answer the following questions.
Descriptive Statistics |
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Birth_Order |
Mean |
Std. Deviation |
N |
1 |
57.66 |
23.947 |
250 |
2 |
59.44 |
23.479 |
250 |
3 |
60.26 |
23.408 |
250 |
Total |
59.12 |
23.606 |
750 |
Tests of Between-Subjects Effects |
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Source |
Type III Sum of Squares |
df |
Mean Square |
F |
Sig. |
Partial Eta Squared |
Birth Order |
885.048 |
2 |
442.524 |
.794 |
.453 |
.002 |
Error |
416490.152 |
747 |
557.550 |
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Total |
3038756.000 |
750 |
Problem: Researchers were interested in determining whether there were any differences in the tendency to procrastinate based on birth order, i.e. first, second, or third child born.
a.
The problem is one-way ANOVA
(Analysis of Variance).
Null hypothesis-H0:
mu1=mu2=mu3 (Means are all
SAME)
where, mu1=mean based on first order; mu2=mean based on second
order and mu3=mean based on third order
Alternative Hypothesis-H1: atleast one mui is
different from remaining ones (Means differ significantly)
b.
Total sample size=N= (250+250+250) = 750
c.
Independent variable:
Since, it is one-way ANOVA it has only one independent variable (or
factor). It is typically a categorical variable. It is controlled
by the experimenter. Here, Birth level form independent variable
with levels ("1","2","3").
Dependent variable:
It is the variable that is the "result" of independent
variable.
## From ANOVA table we obtain,
d.
Test statistic value = F-statistic value = F0 =
0.794
[F-value=Mean square of birth order / Mean Square Error]
e.
p-value=0.453
[p-value=P{F(2,747) < F0}=0.453]
f.
assume α = 0.05
Comparison: p-value (0.453) is greater than alpha (0.05).We
fail to Reject H0.
Conclusion: There were NO significant
differences in the tendency to procrastinate based on birth order,
i.e. first, second, or third child born.
g.
NO, we DO NOT need post hoc analysis. Because,only
if we Reject H0 in above ANOVA we go for further analysis. Here, we
fail to Reject H0.
[post hoc analysis is needed when we have to find out if category
is significant, which level of category (or combination of
category) is significant.]