In: Statistics and Probability
Participant |
Minutes |
1 |
150 |
2 |
45 |
3 |
67 |
4 |
221 |
5 |
30 |
6 |
109 |
7 |
78 |
8 |
126 |
9 |
135 |
10 |
58 |
11 |
89 |
12 |
90 |
13 |
93 |
14 |
108 |
15 |
119 |
16 |
185 |
17 |
100 |
18 |
109 |
19 |
189 |
20 |
167 |
Given: = 93, s = 113.4, = 49.84 , n = 20, = 0.05
(a) The Hypothesis:
H0: = 93
Ha: > 93
This is a right tailed Test.
(b) The Test Statistic: Since the population standard deviation is unknown, we use the students t test.
The test statistic is given by the equation:
(c) The Critical Value: The critical value (Right Tail) at = 0.05, for df = 19, tcritical = +1.691
The p Value: The p value (Right Tail) for t = 2.42, for degrees of freedom (df) = n-1 = 19, is; p value = 0.0105
The Decision Rule: If tobserved is > tcritical, then Reject H0
Also if P value is < , Then Reject H0.
The Conclusion:
Since tobserved (2.44) is > tcritical (1.691), We Reject H0. There is sufficient evidence at the 95% significance level to conclude that the mean time spent on listening to podcasts is greater than 93.
___________________________________________________
Calculation for the mean and standard deviation:
Mean = Sum of observation / Total Observations
Standard deviation = SQRT(Variance)
Variance = Sum Of Squares (SS) / n - 1, where SS = SUM(X - Mean)2.
Participant | Minutes | Mean | (X - Mean)2 |
1 | 150 | 113.4 | 1339.56 |
2 | 45 | 113.4 | 4678.56 |
3 | 67 | 113.4 | 2152.96 |
4 | 221 | 113.4 | 11577.76 |
5 | 30 | 113.4 | 6955.56 |
6 | 109 | 113.4 | 19.36 |
7 | 78 | 113.4 | 1253.16 |
8 | 126 | 113.4 | 158.76 |
9 | 135 | 113.4 | 466.56 |
10 | 58 | 113.4 | 3069.16 |
11 | 89 | 113.4 | 595.36 |
12 | 90 | 113.4 | 547.56 |
13 | 93 | 113.4 | 416.16 |
14 | 108 | 113.4 | 29.16 |
15 | 119 | 113.4 | 31.36 |
16 | 185 | 113.4 | 5126.56 |
17 | 100 | 113.4 | 179.56 |
18 | 109 | 113.4 | 19.36 |
19 | 189 | 113.4 | 5715.36 |
20 | 167 | 113.4 | 2872.96 |
Total | 2268 | Total | 47204.8 |
Mean | 113.4 | Variance | 2484.46316 |
SD | 49.84 |