Question

CALCULATE THE MEAN value : Mean(x) = x0 = 1/N * ∑_iⁿ x_{i and the Stardandar deviacion :}     σ = √ (∑_iⁿ (xi-x0)² / (N-1) BOTH USING MATLAB EMERGENCY PLEASE . THE DATA IS BELOW ....SHOW THE STEPS AND THE GRAPHS ...THERE ARE R1 AND R5 for the data

R1

1.3004560111742451e+01
1.2989489582476999e+01
1.2992918145494006e+01
1.3015926219975810e+01
1.3003113745531683e+01
1.3009060588116746e+01
1.3006255988139626e+01
1.3006525855308004e+01
1.3015986719424999e+01
1.3015607658994400e+01

R5

1.2896465697037076e+01
1.3078048708539365e+01
1.2947635768569747e+01
1.3036655293457565e+01
1.2970848809276067e+01
1.3044710696683399e+01
1.3036858101292060e+01
1.3033168310496990e+01
1.2872334019855321e+01
1.2853995527962450e+01

Answer 1

Solution:

By using MATLAB:

clc

clear all

close all

format short

R1=[1.3004560111742451e+01

1.2989489582476999e+01

1.2992918145494006e+01

1.3015926219975810e+01

1.3003113745531683e+01

1.3009060588116746e+01

1.3006255988139626e+01

1.3006525855308004e+01

1.3015986719424999e+01

1.3015607658994400e+01];

R5=[1.2896465697037076e+01

1.3078048708539365e+01

1.2947635768569747e+01

1.3036655293457565e+01

1.2970848809276067e+01

1.3044710696683399e+01

1.3036858101292060e+01

1.3033168310496990e+01

1.2872334019855321e+01

1.2853995527962450e+01];

disp('Mean of R1 is');

M1=sum(R1)/length(R1)

disp('Mean of R5 is');

M2=sum(R5)/length(R5)

disp('Standard deviation of R1 is');

sqrt(sum((R1-M1).^2)/(length(R1)-1))

disp('Standard deviation of R5 is');

sqrt(sum((R5-M2).^2)/(length(R5)-1))

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Thank you.