Question

Given the number of trials, n, and the probability of success, p, find the following probabilities.

a. N = 12, p = 0.06 P(3 successes)

b. N = 18, p = 0.96 P(2 failures)

c. N = 5, p = 0.28 P(at least 3 successes)

d. N = 90, p = 0.04 P(no more than 4 successes)

Answer 1

a) This is a binomial distribution question with
n = 12
p = 0.06
q = 1 - p = 0.94
where

This is a binomial distribution question with
n = 18
p = 0.96
q = 1 - p = 0.04
where

2 failure means 18-2 = 16 success
c) This is a binomial distribution question with
n = 5
p = 0.28
q = 1 - p = 0.72
where

This is a binomial distribution question with
n = 90
p = 0.04
q = 1 - p = 0.96
where

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