In: Statistics and Probability
Analysis of Variance results:
Responses: Self-esteem
Factors: handedness
Response statistics by factor
handedness |
n |
Mean |
Std. Dev. |
Std. Error |
left |
7 |
4.2857143 |
3.0937725 |
1.1693361 |
mixed |
4 |
8 |
2.1602469 |
1.0801234 |
right |
9 |
5.4444444 |
3.4681087 |
1.1560362 |
ANOVA table
Source |
DF |
SS |
MS |
F-Stat |
P-value |
handedness |
2 |
35.299206 |
17.649603 |
1.7896918 |
0.1971 |
Error |
17 |
167.65079 |
9.8618114 |
||
Total |
19 |
202.95 |
Tukey HSD results (95% level)
left subtracted from
Difference |
Lower |
Upper |
P-value |
|
mixed |
3.7142857 |
-1.3351574 |
8.7637289 |
0.1728 |
right |
1.1587302 |
-2.9011749 |
5.2186352 |
0.7481 |
mixed subtracted from
Difference |
Lower |
Upper |
P-value |
|
right |
-2.5555556 |
-7.3966838 |
2.2855727 |
0.386 |
A ANOVA was run to test the hypothesis to determine if there would be significant difference in self-esteem scores of participants who are left handed, right handed or mixed.
Give a report on the findings.
Was there any significance in difference?
Run a post hoc test even if findings are not significant.
From the ANOVA table, an F value of 1.7896918 was calculated. At
df1 = 2 and df2 = 17, the p value was calculated as 0.1971. The
decision value being that since the p value was >
(0.05), we fail to reject the null hypothesis, that is the
differences were not significant.
The ANOVA Table
Source | SS | DF | Mean Square | F | Fcv | p |
Between | 35.299206 | 2.0 | 17.649603 | 1.788000 | 3.5915 | 0.1974 |
Within/Error | 167.797625 | 17.0 | 9.870449 | |||
Total | 203.10 | 19.0 |
The post Hoc Test
Left | 4.2857143 | ||||||
Mixed | 8 | ||||||
Right | 5.4444444 | ||||||
Difference | 1 / ni + 1/nj | MSE | q critical | ME | Left | Right | |
Left - Mixed | 3.7142857 | 0.39285714 | 9.87 | 2.567185 | 5.055139 | -1.34085 | 8.769425 |
Left - Right | 1.1587301 | 0.25396825 | 9.87 | 2.567185 | 4.064485 | -2.90575 | 5.223215 |
Mixed - Right | 6.8412699 | 0.36111111 | 9.87 | 2.567185 | 4.846589 | 1.994681 | 11.68786 |
A Tukeys post Hoc test was conducted, and the method used was the method of Confidence Interval, whic is given by
Difference (q critical / sqrt(2) )* Sqrt(MSE * [(1 / ni + 1 / nj)]
Please not: We take the absolute value of the difference
Where q critical is tukeys q critical found from tukeys table for the level of significance where on the horizontal we have k = number of treatments and df error on the vertical.
Here = 0.05, df error = 17 and number of treatments = 3 (since df1 = k - 1 = 2)
Therefore tukeys critical = 3.63
MSE = 9.8618114
If the confidence interval comes up with different signs, then the differences are not significant as is the case we see for left subtracted from mixed, left subtracted from right , where the confidence interval for each has different signs, but for mix subtracted from right, the signs are the same, which means that there is a statistical difference between these 2 values.
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