Question

In: Statistics and Probability

Analysis of Variance results: Responses: Self-esteem Factors: handedness Response statistics by factor handedness n Mean Std....

Analysis of Variance results:


Responses: Self-esteem
Factors: handedness

Response statistics by factor

handedness

n

Mean

Std. Dev.

Std. Error

left

7

4.2857143

3.0937725

1.1693361

mixed

4

8

2.1602469

1.0801234

right

9

5.4444444

3.4681087

1.1560362

ANOVA table

Source

DF

SS

MS

F-Stat

P-value

handedness

2

35.299206

17.649603

1.7896918

0.1971

Error

17

167.65079

9.8618114

Total

19

202.95

Tukey HSD results (95% level)


left subtracted from

Difference

Lower

Upper

P-value

mixed

3.7142857

-1.3351574

8.7637289

0.1728

right

1.1587302

-2.9011749

5.2186352

0.7481

mixed subtracted from

Difference

Lower

Upper

P-value

right

-2.5555556

-7.3966838

2.2855727

0.386

A ANOVA was run to test the hypothesis to determine if there would be significant difference in self-esteem scores of participants who are left handed, right handed or mixed.

Give a report on the findings.

Was there any significance in difference?

Run a post hoc test even if findings are not significant.

Solutions

Expert Solution

From the ANOVA table, an F value of 1.7896918 was calculated. At df1 = 2 and df2 = 17, the p value was calculated as 0.1971. The decision value being that since the p value was > (0.05), we fail to reject the null hypothesis, that is the differences were not significant.

The ANOVA Table

Source SS DF Mean Square F Fcv p
Between 35.299206 2.0 17.649603 1.788000 3.5915 0.1974
Within/Error 167.797625 17.0 9.870449
Total 203.10 19.0

The post Hoc Test

Left 4.2857143
Mixed 8
Right 5.4444444
Difference 1 / ni + 1/nj MSE q critical ME Left Right
Left - Mixed 3.7142857 0.39285714 9.87 2.567185 5.055139 -1.34085 8.769425
Left - Right 1.1587301 0.25396825 9.87 2.567185 4.064485 -2.90575 5.223215
Mixed - Right 6.8412699 0.36111111 9.87 2.567185 4.846589 1.994681 11.68786

A Tukeys post Hoc test was conducted, and the method used was the method of Confidence Interval, whic is given by

Difference (q critical / sqrt(2) )* Sqrt(MSE * [(1 / ni + 1 / nj)]

Please not: We take the absolute value of the difference

Where q critical is tukeys q critical found from tukeys table for the level of significance where on the horizontal we have k = number of treatments and df error on the vertical.

Here = 0.05, df error = 17 and number of treatments = 3 (since df1 = k - 1 = 2)

Therefore tukeys critical = 3.63

MSE = 9.8618114

If the confidence interval comes up with different signs, then the differences are not significant as is the case we see for left subtracted from mixed, left subtracted from right , where the confidence interval for each has different signs, but for mix subtracted from right, the signs are the same, which means that there is a statistical difference between these 2 values.

_____________________________________________________________


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