Question

In: Statistics and Probability

1a Fusella (1970) had participants watch a screen, looking for brief presentations of a small blue...

1a

Fusella (1970) had participants watch a screen, looking for brief presentations of a small blue arrow. On some trials, the participants were also asked to form a mental image. The number of errors in the task was counted. The results for a sample of n = 6, show that  MD = 10 The difference score had SS = 80. Do the data indicate a significant difference between the two conditions: forming a mental image and not forming a mental image? Use a two-tailed test with α = .01

The null hypothesis in words is

Group of answer choices

a. The number of errors when participants form a mental image is not significantly different from the number of errors when participants do not form a mental image.

b. The number of errors when participants form a mental image is significantly different from the number of errors when participants do not form a mental image.

c. The number of errors when participants form a mental image is not significantly greater than the number of errors when participants do not form a mental image.

d. The number of errors when participants form a mental image is significantly greater than the number of errors when participants do not form a mental image.

1b)

The alternative hypothesis in symbols is

Group of answer choices

a. H1: µ1= µ2

b. H1: µ1> µ2

c. H1: µD= 0

d. H1: µD> 0

e. H1: µD≠ 0

f. H1: MD = 4.3

g. H1: MD ≠ 4.3

h. H1: µD≤ 0

1c)

The critical t-values are

Group of answer choices

a.±4.032

b. ±3.365

c. ±2.571

d. ±2.015

1d)The t-statistic is

1e)

Compute Estimated Cohen’s d

Cohen's d =

1f)

Your decision is

Group of answer choices

a. Reject the null hypothesis and conclude that the number of errors when participants form a mental image is significantly different from the number of errors when participants do not form a mental image

b. Reject the null hypothesis and conclude that the number of errors when participants form a mental image is not significantly different from the number of errors when participants do not form a mental image

c. Fail to reject the null hypothesis and conclude that the number of errors when participants form a mental image is significantly different from the number of errors when participants do not form a mental image

d. Fail to reject the null hypothesis and conclude that the number of errors when participants form a mental image is not significantly different from the number of errors when participants do not form a mental image

Solutions

Expert Solution

(1a)

Correct option:

a. The number of errors when participants form a mental image is not significantly different from the number of errors when participants do not form a mental image.

(1b)

Correct option:

e. H1: µD≠ 0

(1c)

Correct option:

a     .± 4.032

Explanation:

= 0.01

df = 6 - 1 =5

From Table, critical values of t = 4.032

(1d)

6.1237

Explanation:

The t statistic is got as follows:

n = 6

= 10

The t statistic is given by:

(1e)

2.5

Explanation:
Cohen's d is given by:

(1f)

Correct option:

a. Reject the null hypothesis and conclude that the number of errors when participants form a mental image is significantly different from the number of errors when participants do not form a mental image


Related Solutions

Fusella (1970) had participants watch a screen, looking for brief presentations of a small blue arrow....
Fusella (1970) had participants watch a screen, looking for brief presentations of a small blue arrow. On some trials, the participants were also asked to form a mental image. The number of errors in the task was counted. The results for a sample of n = 6, show that  MD = 4.3 The difference score had SS = 63. Do the data indicate a significant difference between the two conditions: forming a mental image and not forming a mental image? Use...
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