In: Chemistry
A voltaic cell consists of a Zn/Zn2+ anode and a Ni/Ni2+ cathode at 25 ∘C. The initial concentrations of Ni2+ and Zn2+ are 1.7 M and 0.12 M , respectively. The volume of half-cells is the same.
What is the concentration of Ni2+ when the cell potential falls to 0.456 V ?
Enter your answer to 4 decimal places and in units of mM.
Zn2+ (aq) + 2 e- ⟶Zn(s) E° = -0.76 V
Ni2+ (aq) + 2 e- ⟶ Ni(s) E° = -0.23 V