In: Statistics and Probability
A study was conducted regarding the wearing of masks by the public during the COVID 19 reopening. They surveyed 900 people to see whether the people were complying with the mask-wearing guidelines. The researchers used 85% as an assumed proportion of compliance but hoped there would be evidence to suggest the proportion of people in compliance is higher than 85%. So, the hypotheses are given below.
H0:p=0.85, Ha:p>0.85
For the different sample proportions given below, label them as either: (note, one should be A, one should be B and one should be C)
1.) p=0.89
2.) p=0.844
3.) p=0.86
1) H0: p = 0.85
Ha: p > 0.85
The test statistic is
P-value = P(Z > 3.36)
= 1 - P(Z < 3.36)
= 1 - 0.9996
= 0.0004
Since the P-value is very small, so we should reject H0.
Option - C) Providing STRONG evidence against the null hypothesis and in support of the alternative hypothesis.
2) H0: p = 0.85
Ha: p > 0.85
The test statistic is
P-value = P(Z > -0.50)
= 1 - P(Z < -0.50)
= 1 - 0.3085
= 0.6915
Since the P-value is larger, so we should not reject H0.
Option - A) Providing no evidence against the null hypothesis and in support of the alternative hypothesis.
3) H0: p = 0.85
Ha: p > 0.85
The test statistic is
P-value = P(Z > 0.84)
= 1 - P(Z < 0.84)
= 1 - 0.7995
= 0.2005
Since the P-value is greater, so we should not reject H0.
Option - A) Providing some evidence, but not a lot of evidence, against the null hypothesis and in support of the alternative hypothesis.