Question

The electric field midway between two equal but opposite point charges is 567 N/C , and the distance between the charges is 16.0 cm.

a)What is the magnitude of the charge on each?

Answer 1

Given that

distance between the two charges d = 0.16m

k =8.99 x 10⁹ N/C

The electric field midway between two equal but opposite point charges is E _tot= 567 N/C

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The net electric feild midway between the two charges is

            E_tot = 2E

             E = E_tot/2

                = (567 N/C)/2

                = 283.5 N/C

The electricfield due to charge q is

              E =kq/r²

Here r = d/2 = 0.08m

      So the magnitude of the charge is

             q = Er²/k

                = (283.5 N/C)(0.08 m)²/(8.99 x10⁹ )

                = 2.018x10^-10 C