Question

In: Mechanical Engineering

A model of an air ship is to be studied. The prototype is envisaged to be...

A model of an air ship is to be studied. The prototype is envisaged to be 8 m long with a diameter of 750 mm and the model is to be 300 mm long. What should the diameter of the model be? What should the diameter velocity in a wind tunnel be to simulate actual conditions? If the drag on the full model is found to be x N, what would the drag on the prototype be?

Solutions

Expert Solution

For geometric similarity, all the dimensions between prototype and model must be scaled in the same ratio.

Geometric scaling = 8 / 0.3 = 0.75 / Dmodel

Dmodel = 0.028125 m = 28.125 mm

For simulating actual conditions, Reynolds number should be the same.

Re = V*D / neu

Since both model and prototype are tested in air, kinematic viscosity neu is same for both.

Vprototype * 0.75 = Vmodel * 0.028125

Vmodel  / Vprototype = 26.67

Drag force D = Cd * 1/2 * rho * V2 * A

Since Area A ~ D2, we get

Dmodel  / Dprototype = (Vmodel  / Vprototype )2 * (Dmodel  / Dprototype )2

x/ Dprototype = 26.672 * (0.028125 / 0.75)2

Dprototype = x N


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