In: Physics
A weightlifter works out at the gym each day. Part of her routine is to lie on her back and lift a 41 kg barbell straight up from chest height to full arm extension, a distance of 0.55 m .
1. How much work does the weightlifter do to lift the barbell one time?
2. If the weightlifter does 25 repetitions a day, what total energy does she expend on lifting, assuming a typical efficiency for energy use by the body (25%).
3. How many 430 Calorie donuts can she eat a day to supply that energy? Express your answer using two significant figures.
Solution:-
A weightlifter works out at the gym each day, part of her routine is to lie on her back and lift a 41kg barbell straight up from chest height and to full arm extension a distance of 0.55m
Work = force * distance
Weight = 41*9.8
Work = 41*9.8*0.55
Work = 220.99N-m
Work = 221 J
2) If the weightlifter does 25 repetitions a day , calculate total energy,
Work = Energy
Energy = (220.99J/rep)*(25rep)
Energy = 5524.75
Energy = 5525J if 100% efficiency
Since she is only 25% effiecincy she has to expend
4*5524.75J
= 22099 J
22099J of energy to do 5524.75 J of work.
3) How many 430 calories donuts can she eat a day to supply that energy
4.18J = 1 Calorie
22099/4.18 = 5286.84calories/430donuts = 12.29 donuts
12 donuts (two significant figures)