Question

A)

Titration of an acidic solution of Na2C2O4 with KMnO4(aq).

Which species is the reducing agent?

Express your answer as an ion.

I know the reducing agent is the Na2C2O4 but I need the ION form.

B)A voltaic cell utilizes the following reaction:
2Fe3+(aq)+H2(g)→2Fe2+(aq)+2H+(aq)

.What is the emf for this cell when [Fe3+]= 3.50 M , PH2= 0.99 atm , [Fe2+]= 1.1×10⁻³ M , and the pHin both compartments is 4.15?

Express your answer using two significant figures.

0.771 V is not correct

Answer 1

A) Na2C2O4 is a salt, it exists as 2Na+ and C2O4 2-. In this titration KMnO4 is the oxidizing agent (ion form MnO4-). Na2C2O4 is the reducing agent ( ion form C2O4 2-)

B) the answer is 1.2 V.

If there is any calculation mistake kindly ignore. But the process is spot on.

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