In: Statistics and Probability
The blood pressure measurements of a single patient were taken by twelve different medical students and the results are listed below. Answer parts a-c.
systolic (x) |
138 |
132 |
141 |
119 |
123 |
120 |
127 |
129 |
125 |
143 |
142 |
138 |
||
diastolic (y) |
92 |
91 |
99 |
84 |
88 |
82 |
83 |
84 |
82 |
96 |
104 |
97 |
a. Find the value of the linear correlation coefficient r.
b. Find the critical values of r from the table showing the critical values for the Pearson correlation coefficient using
alpha=0.05
c. Is there sufficient evidence to conclude that there is a linear correlation between the two variables?
Solution:
X | Y | XY | X^2 | Y^2 | |
138 | 92 | 12696 | 19044 | 8464 | |
132 | 91 | 12012 | 17424 | 8281 | |
141 | 99 | 13959 | 19881 | 9801 | |
119 | 84 | 9996 | 14161 | 7056 | |
123 | 88 | 10824 | 15129 | 7744 | |
120 | 82 | 9840 | 14400 | 6724 | |
127 | 83 | 10541 | 16129 | 6889 | |
129 | 84 | 10836 | 16641 | 7056 | |
125 | 82 | 10250 | 15625 | 6724 | |
143 | 96 | 13728 | 20449 | 9216 | |
142 | 104 | 14768 | 20164 | 10816 | |
138 | 97 | 13386 | 19044 | 9409 | |
SUM | 1577 | 1082 | 142836 | 208091 | 98180 |
Putting values , we get
r = 0.8878
b)
n = 12
df = n - 2 = 12 - 2 = 10
= 0.05
Using the critical value table for Pearson correlation coefficient, (two tailed )
Critical value are 0.576
c)
r = 0.8878
| r | = | 0.8878| = 0.8878
r > 0.576
reject H0
significance correlation.
YES , there is sufficient evidence to conclude that there is a linear correlation between the two variables.