In: Physics
If the cross-sectional area of the manometer is 10 cm2 and the amount of water added is 50 ml, what will be the height difference between the two arms of the manometer?
Volume of water added = 50 ml = m3
Cross sectional area of monometer = 10
Pressure due to fluid =
Here, Pressure due to water = Pressure difference in Manometer [Manometer contains mercury. Density of mercury is 13.6 times density of water]
Hence,
Therefore, the height difference between the two arms of the manomemter will be 0.37cm.