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In: Statistics and Probability

Continuing the quality improvement effort first described in the chapter 6 Managing Ashland Multicomms services case,...

Continuing the quality improvement effort first described in the chapter 6 Managing Ashland Multicomms services case, the target upload speed for AMS internet service subscribers has been monitored.As before, upload speeds are measured on a standard scale in which the target value is 1.0. Data collected over the past year indicate that the upload speeds are approximately normally distributed, with a mean of 1.005 and a standard deviation of 0.10.

Each day, at 25 random times, the upload speed is measured. Assuming that the distribution has not changed from what it was in the past year, what is the probability that the mean upload speed is

a. less than 1.0?

b. between 0.95 and 1.0?

c. between 1.0 and 1.05?

d. less than 0.95 or greater than 1.05?

e. Suppose that the mean upload speed of today’s sample of 25 is 0.952. What conclusion can you reach about the mean upload speed today based on this result? Explain.

2. Compare the results of AMS Problem 1 ( a) through ( d) to those of AMS Problem 1 in Chapter 6 on page 221. What conclusions can you reach concerning the differences?

Expert Solution

Here in this Question, Continuing the quality improvement effort first described in the chapter 6 Managing Ashland Multicomms services case, the target upload speed for AMS internet service subscribers has been monitored.As before, upload speeds are measured on a standard scale in which the target value is 1.0. Data collected over the past year indicate that the upload speeds are approximately normally distributed, with a mean of 1.005 and a standard deviation of 0.10.

Now we need to calculate the probability that sampling Distribution for sample mean is as below,

Please note that the above probability is calculated using Standerd normal z-table.

Now comparing all results from a to e we concluded that there is 58% chance that the sample mean will between 1 to 1.05 and there is 39.8% chance that the sample mean will between 0.95 to 1.05.

This is the simple answer of your 1st Question.

Hope you understood how to find probability using Standerd normal z-table.

Thank you.

orchestra answered 1 year ago

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