Question

In: Statistics and Probability

The average height of women in the freshman class has historically been 5'4" with a standard...

The average height of women in the freshman class has historically been 5'4" with a standard deviation of 3". Suppose we take a sample of 50 women in the current freshman class and find an average height of 5'5". Which distribution should we use to standardize?

Expert Solution

Solution :

Given that,

mean = = 54

standard deviation = = 3

n = 50

= 54

= / n = 3 / 50 = 0.4243

P( > 55) = 1 - P( < 55 )

= 1 - P[( - ) / < ( 55 - 54) / 0.4243 ]

= 1 - P(z < 2.36)

Using z table,

= 1 - 0.9909

= 0.0091

probability = 0.0091

orchestra answered 1 year ago

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