Question

In: Statistics and Probability

Carolina Wood Products, Inc., a major manufacturer of household furniture, is interested in predicting expenditures on...

Carolina Wood Products, Inc., a major manufacturer of household furniture, is interested in predicting expenditures on furniture (FURN) for the entire United States.

Period FURN ($Billions) Time
Mar-07 61.1 1
Jun-07 59.8 2
Sep-07 59 3
Dec-07 58 4
Mar-08 56.2 5
Jun-08 58.1 6
Sep-08 59.2 7
Dec-08 61.4 8
Mar-09 63.7 9
Jun-09 67.4 10
Sep-09 71.1 11
Dec-09 74.1 12
Mar-10 77.3 13
Jun-10 80.2 14
Sep-10 82.4 15
Dec-10 85.7 16
Mar-11 88.9 17
Jun-11 92.3 18
Sep-11 95.2 19
Dec-11 99.6 20
Mar-12 100.4 21
Jun-12 104.4 22
Sep-12 108.3 23
Dec-12 110.7 24
Mar-13 111.8 25
Jun-13 113.2 26
Sep-13 116.4 27
Dec-13 117.2 28
Mar-14 122.8 29
Jun-14 127.4 30
Sep-14 129.2 31
Dec-14 132.7 32
Mar-15 136.7 33
Jun-15 138.5 34
Sep-15 138 35
Dec-15 138.7 36
Mar-16 144.4 37
Jun-16 143 38
Sep-16 142.7 39
Dec-16 139.3 40
Mar-17 41
Jun-17 42
Sep-17 43
Dec-17 44
  1. Estimate the bivariate linear trend model for the data where TIME=1 for 2007, Q1 through TIME=40 for 2016, Q4.

    FURN = a + b(TIME)

  2. Evaluate this model in one paragraph, with particular emphasis on its usefulness in forecasting.
  3. Prepare a time-trend forecast of furniture and household equipment expenditures for 2017 based on the model in (b).
    Period Time Trend Forecast
    2017 Q1 41
    2017 Q2 42
    2017 Q3 43
    2017 Q4 44

Solutions

Expert Solution

a)

ΣX ΣY Σ(x-x̅)² Σ(y-ȳ)² Σ(x-x̅)(y-ȳ)
total sum 820 3966.5 5330 36121.3 13746.35
mean 20.50 99.16 SSxx SSyy SSxy

sample size ,   n =   40          
here, x̅ = Σx / n=   20.50   ,     ȳ = Σy/n =   99.16  
                  
SSxx =    Σ(x-x̅)² =    5330.0000          
SSxy=   Σ(x-x̅)(y-ȳ) =   13746.4          
                  
estimated slope , ß1 = SSxy/SSxx =   13746.4   /   5330.000   =   2.5791
                  
intercept,   ß0 = y̅-ß1* x̄ =   46.2919          
                  
so, regression line is   Ŷ =   46.2919   +   2.5791   *x

b)

SSE=   (SSxx * SSyy - SS²xy)/SSxx =    668.715
      
std error ,Se =    √(SSE/(n-2)) =    4.195
      
correlation coefficient ,    r = Sxy/√(Sx.Sy) =   0.9907
      
R² =    (Sxy)²/(Sx.Sy) =    0.9815

As we can see R square = 98.15 % means 98.15% variance in FURN can be explained by time period. Model is good.

C)

Predicted Y at X=   41   is                  
Ŷ =   46.29192   +   2.579053   *   41   =   152.033

Predicted Y at X=   42   is                  
Ŷ =   46.29192   +   2.579053   *   42   =   154.612

Predicted Y at X=   43   is                  
Ŷ =   46.29192   +   2.579053   *   43   =   157.191

Predicted Y at X=   44   is                  
Ŷ =   46.29192   +   2.579053   *   44   =   159.770

THANKS

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