In: Statistics and Probability
The following hypotheses are given. H0: p ≤ 0.83 H1: p > 0.83 A sample of 128 observations revealed that = 0.73. At the 0.05 significance level, can the null hypothesis be rejected?
a. State the decision rule. (Round the final answer to 3 decimal places.) Reject CorrectH0 and and accept CorrectH1 if z>... or z<
Here, we have to use one sample z test for the population proportion.
The null and alternative hypotheses for this test are given as below:
H0: p ≤ 0.83 versus Ha: p > 0.83
This is an upper tailed test.
We are given
Level of significance = α = 0.05
Critical Z value = 1.6449
(by using z-table)
Decision rule: Reject H0 if test statistic Z > 1.645
Test statistic formula for this test is given as below:
Z = (p̂ - p)/sqrt(pq/n)
Where, p̂ = Sample proportion, p is population proportion, q = 1 - p, and n is sample size
n = sample size = 128
p̂ = x/n = 0.73
p = 0.83
q = 1 - p = 0.17
Z = (p̂ - p)/sqrt(pq/n)
Z = (0.73 - 0.83)/sqrt(0.83*0.17/128)
Z = -3.0119
Test statistic = -3.0119
P-value = 0.9987
(by using z-table)
P-value > α = 0.05
So, we do not reject the null hypothesis.