In: Statistics and Probability
The American Bankers Association reported that, in a sample of 150 consumer purchases in France, 60 were made with cash, compared with 23 in a sample of 55 consumer purchases in the United States. Construct a 95 percent confidence interval for the difference in proportions. (Round your intermediate value and final answers to 4 decimal places.) The 95 percent confidence interval is from to .
Solution :
Given that,
n1 = 150
x1 = 60
1 = x1 / n1 = 0.40
n2 =55
x2 = 23
2 = x2 / n2 = 0.418
1) Point estimate of difference between two proportions
= 1 - 2
= 0.40 - 0.418
= -0.018
2)
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Margin of error = *
=
=
= 0.152
3) Required interval is
Point estimate Margin of error
-0.018 0.152
(-0.17, 0.134)
The 95 percent confidence interval is -0.17 to 0.134.