Question

In: Mechanical Engineering

Please calculate the air consumption rate below in litre/sec The forge contains one large pneumatically operated...

Please calculate the air consumption rate below in litre/sec

The forge contains one large pneumatically operated hammer driven by 1 double acting cylinder, piston rod at one end only, bore 400mm, piston rod diameter 100mm, stroke 680mm. The piston executes 9 up strokes and 9 down strokes in 1.5 minutes then does nothing for 3.5 minutes, then repeats the cycle. The air is regulated to enter at 590 kPa.g. and in this machine the pressure in the cylinder may be taken to be this for the full stroke.

Expert Solution

Volume of pneumatic cylinder:

(/4) d².L

d = Bore diameter = 400mm

L = Stroke length = 680mm

Therefore,

V = (/4) x 400² x 680

V = 85.45 x 10⁶ mm³

This is the volume occupied by piston in one stroke.

In 1.5 minutes, 9 suction strokes takes place.

Hence, 85.45 x 10⁶ x9 = 769.06 x 10⁶ mm³

1.5 min = 90 seconds

Air consumption rate is :

769.06 x 10⁶ mm³ / 90 seconds

Hence, air consumption rate per sec is, 769.09 x 10⁶/ 90 = 8.545 x 10⁹ mm³/sec

We have to calculate air consumption rate in lit/sec,

As, 1mm³ = 1 x 10^-6 lit/sec

Therefore, 8.5451 lit/sec

Air consumption is 8.5451 lit/sec.

samet mamat answered 2 years ago

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