Question

In: Statistics and Probability

Rhinoviruses typically cause common colds. In a test of the effectiveness of echinacea, 40 of the...

Rhinoviruses typically cause common colds. In a test of the effectiveness of echinacea, 40 of the 45 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 88 of the 103 subjects developed rhinovirus infections. We want to use a 0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Test the claim using a hypothesis test.

Group of answer choices

A.P value=0.572; fail to reject H0

B.P value=0.508; fail to reject H0

C.P value=0.605; fail to reject H0

D.P value=0.501; fail to reject H0

Solutions

Expert Solution

x1                =    40 x2                =    88
1=x1/n1 = 0.8889 2=x2/n2 = 0.8544
n1                       = 45 n2                       = 103
estimated prop. diff =p̂1-p̂2    = 0.0345
pooled prop p̂ =(x1+x2)/(n1+n2)= 0.8649
std error Se=√(p̂1*(1-p̂1)*(1/n1+1/n2) = 0.0611
test stat z=(p̂1-p̂2)/Se = 0.565
P value   = 0.5721

option A is correct

A.P value=0.572; fail to reject H0


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