In: Statistics and Probability
Given the sample data.
x: Given the sample data.
x: 23, 17,15,32,25
(a)
Find the range. (Enter an exact number.)
(b)
Verify that Σx = 112 and Σx2 =
2,692. (For each answer, enter an exact number.)
Σx =
Σx2 =
(c)
Use the results of part (b) and appropriate computation formulas
to compute the sample variance s2 and sample
standard deviation s. (For each answer, enter a number.
Round your answers to two decimal places.)
s2 =
s =
(d)
Use the defining formulas to compute the sample variance
s2 and sample standard deviation s.
(For each answer, enter a number. Round your answers to two decimal
places.)
s2 =
s =
(e)
Suppose the given data comprise the entire population of all
x values. Compute the population variance
σ2 and population standard deviation
σ. (For each answer, enter a number. Round your answers to
two decimal places.)
σ2 =
σ =
(a)
Range = Maximum - Minimum = 32 - 15 = 17
(b)
x | x2 |
23 | 529 |
17 | 289 |
15 | 225 |
32 | 1024 |
25 | 625 |
Total = 112 | 2692 |
Thus, we verify:
(c)
Sample Variance (s2) is given by:
Sample Standard Deviation (s) is given by:
(d)
Sample Mean () is given by:
x | x- | (x - )2 |
23 | 0.6 | 0.36 |
17 | -5.4 | 29.16 |
15 | -7.4 | 54.76 |
32 | 9.6 | 92.16 |
25 | 2.6 | 6.76 |
Total = | 183.20 |
Sample Variance (s2) is given by:
Sample Standard Deviation (s) is given by:
(e)
Population Mean () is given by:
x | x- | (x - )2 |
23 | 0.6 | 0.36 |
17 | -5.4 | 29.16 |
15 | -7.4 | 54.76 |
32 | 9.6 | 92.16 |
25 | 2.6 | 6.76 |
Total = | 183.20 |
Population Variance () isgiven by:
Population Standard Deviation () is given by: