Question

In: Statistics and Probability

Most married couples have two or three personality preferences in common. A random sample of 374...

Most married couples have two or three personality preferences in common. A random sample of 374 married couples found that 128 had three preferences in common. Another random sample of 558 couples showed that 200 had two personality preferences in common. Let p1 be the population proportion of all married couples who have three personality preferences in common. Let p2 be the population proportion of all married couples who have two personality preferences in common.

(a) Find a 95% confidence interval for p1p2. (Use 3 decimal places.)

lower limit
upper limit

(b) Examine the confidence interval in part (a) and explain what it means in the context of this problem. Does the confidence interval contain all positive, all negative, or both positive and negative numbers? What does this tell you about the proportion of married couples with three personality preferences in common compared with the proportion of couples with two preferences in common (at the 95% confidence level)?

A. Because the interval contains only positive numbers, we can say that a higher proportion of married couples have three personality preferences in common.

B. Because the interval contains both positive and negative numbers, we can not say that a higher proportion of married couples have three personality preferences in common.

C. We can not make any conclusions using this confidence interval.

D.Because the interval contains only negative numbers, we can say that a higher proportion of married couples have two personality preferences in common.

A random sample of 25 adult male wolves from the Canadian Northwest Territories gave an average weight x1 = 97.4 pounds with estimated sample standard deviation s1 = 7.2 pounds. Another sample of 23 adult male wolves from Alaska gave an average weight x2 = 90.2 pounds with estimated sample standard deviation s2 = 6.7 pounds.(a) Categorize the problem below according to parameter being estimated, proportion p, mean μ, difference of means μ1μ2, or difference of proportions p1p2. Then solve the problem.

A. p

B. μ   

C. μ1μ2

D.p1p2



(b) Let μ1 represent the population mean weight of adult male wolves from the Northwest Territories, and let μ2 represent the population mean weight of adult male wolves from Alaska. Find a 95% confidence interval for μ1μ2. (Use 1 decimal place.)

lower limit
upper limit

(c) Examine the confidence interval and explain what it means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the 95% level of confidence, does it appear that the average weight of adult male wolves from the Northwest Territories is greater than that of the Alaska wolves?

A. Because the interval contains only positive numbers, we can say that Canadian wolves weigh more than Alaskan wolves.

B. Because the interval contains both positive and negative numbers, we can not say that Canadian wolves weigh more than Alaskan wolves.

C. We can not make any conclusions using this confidence interval.

D.Because the interval contains only negative numbers, we can say that Alaskan wolves weigh more than Canadian wolves.

Solutions

Expert Solution

pls upvote...!!!


Related Solutions

Most married couples have two or three personality preferences in common. A random sample of 371...
Most married couples have two or three personality preferences in common. A random sample of 371 married couples found that 130 had three preferences in common. Another random sample of 573 couples showed that 219 had two personality preferences in common. Let p1 be the population proportion of all married couples who have three personality preferences in common. Let p2 be the population proportion of all married couples who have two personality preferences in common. (a) Find a 90% confidence...
Most married couples have two or three personality preferences in common. A random sample of 375...
Most married couples have two or three personality preferences in common. A random sample of 375 married couples found that 134 had three preferences in common. Another random sample of 573 couples showed that 215 had two personality preferences in common. Let p1 be the population proportion of all married couples who have three personality preferences in common. Let p2 be the population proportion of all married couples who have two personality preferences in common. (a) Find a 90% confidence...
A random sample of 364 married couples found that 288 had two or more personality preferences...
A random sample of 364 married couples found that 288 had two or more personality preferences in common. In another random sample of 588 married couples, it was found that only 30 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. (a) Find a 90% confidence interval for...
A random sample of 366 married couples found that 292 had two or more personality preferences...
A random sample of 366 married couples found that 292 had two or more personality preferences in common. In another random sample of 552 married couples, it was found that only 20 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. (a) Find a 95% confidence interval for...
A random sample of 376 married couples found that 296 had two or more personality preferences...
A random sample of 376 married couples found that 296 had two or more personality preferences in common. In another random sample of 586 married couples, it was found that only 20 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. (a) Find a 95% confidence interval for...
A random sample of 366 married couples found that 286 had two or more personality preferences...
A random sample of 366 married couples found that 286 had two or more personality preferences in common. In another random sample of 552 married couples, it was found that only 38 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. (a) Find a 90% confidence interval for...
A random sample of 380 married couples found that 284 had two or more personality perferences...
A random sample of 380 married couples found that 284 had two or more personality perferences in common. In another random sample of 566 married couples, it was found that only 24 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. (a) Find a 90% confidence interval for...
The following table shows the Myers-Briggs personality preferences for a random sample of 406 people in...
The following table shows the Myers-Briggs personality preferences for a random sample of 406 people in the listed professions. E refers to extroverted and I refers to introverted. Personality Type Occupation E I Row Total Clergy (all denominations) 66 41 107 M.D. 73 89 162 Lawyer 52 85 137 Column Total 191 215 406 Use the chi-square test to determine if the listed occupations and personality preferences are independent at the 0.05 level of significance. (a) What is the level...
The following table shows the Myers-Briggs personality preferences for a random sample of 406 people in...
The following table shows the Myers-Briggs personality preferences for a random sample of 406 people in the listed professions. E refers to extroverted and I refers to introverted. Personality Type Occupation E I Row Total Clergy (all denominations) 64 43 107 M.D. 63 99 162 Lawyer 54 83 137 Column Total 181 225 406 (b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least three decimal places. Round the test statistic to...
The following table shows the Myers-Briggs personality preferences for a random sample of 406 people in...
The following table shows the Myers-Briggs personality preferences for a random sample of 406 people in the listed professions. E refers to extroverted and I refers to introverted. Personality Type Occupation E I Row Total Clergy (all denominations) 65 42 107 M.D. 66 96 162 Lawyer 59 78 137 Column Total 190 216 406 Use the chi-square test to determine if the listed occupations and personality preferences are independent at the 0.05 level of significance. (a) What is the level...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT