In: Economics
Given,
q = 12L^0.15 K
Hence,
MP(L) = derivative of q with respect to L
= (d/dL) [12L^0.15 K]
= (12 × 0.15)KL^(0.15 -1)
= 1.8K / L^0.85
MP(K) = derivative of q with respect to K
= (d/dK) [12L^0.15 K]
= 12L^0.15
Now the equality,
[MP(L) / w] = [MP(K) / r]
[(1.8K / L^0.85) / 8] = [(12L^0.15) / 30]
Or, 1.8K / 8L^0.85 = 12L^0.15 / 30
Or, 1.8K × 30 = 12L^0.15 × 8L^0.85
Or, 54K = 96L^(0.15 + 0.85)
Or, 54K = 96L^1
Or, 54K = 96L
Or, L = 54K/96
Or, L = 0.5625K ……. (eq 1)
Budget constraint,
L × w + K × r = 20,000
8L + 30K = 20,000
Now by putting the (eq 1)
8 × 0.5625K + 30K = 20,000
Or, 4.5K + 30K = 20,000
Or, 34.5K = 20,000
Or, K = 20,000/34.5 = 580 (rounded to whole number)
Now by putting it in (eq 1)
L = 0.5625 × 580 = 326
Therefore,
q = 12L^0.15 K
= 12 × 326^0.15 × 580
= 12 × 2.38222 × 580
= 16,580
Answers:
Employees = 326
Capital = 580
Cars = 16,580