In: Statistics and Probability
Student ID | Student ACT Score (Independent Variable) | Student GPA (Dependent Variable) | |||||||
1 | 24 | 3.25 | |||||||
2 | 21 | 2.87 | |||||||
3 | 18 | 2.66 | |||||||
4 | 22 | 3.33 | |||||||
5 | 22 | 2.87 | |||||||
6 | 22 | 3.21 | |||||||
7 | 18 | 2.76 | |||||||
8 | 28 | 3.91 | |||||||
9 | 29 | 3.55 | |||||||
10 | 18 | 2.55 | |||||||
11 | 20 | 2.44 | |||||||
12 | 24 | 3.22 | |||||||
13 | 25 | 3.22 | |||||||
14 | 24 | 3.44 | |||||||
15 | 21 | 3.01 | |||||||
Instructions: Generate on a separate worksheet a standard set of SUMMARY OUTPUT for two-variable regression, and label the worksheet "Simple Regression Output". Then, using the information in this output 1) indicate whether there is a significant relationship between students' ACT scores and their GPAs, and 2) show the general prediction line (i.e., regression equation between these two variables), and 3) use this prediction line to compute the predicted GPA with an ACT score of 20. |
SolutionA:
install analysis tool pak in excel
go to
data>data anlaysis>regression
select y as GPA
x as ACT
you will get
SUMMARY OUTPUT | ||||||
Regression Statistics | ||||||
Multiple R | 0.88358236 | |||||
R Square | 0.780717786 | |||||
Adjusted R Square | 0.763849924 | |||||
Standard Error | 0.194760814 | |||||
Observations | 15 | |||||
ANOVA | ||||||
df | SS | MS | F | Significance F | ||
Regression | 1 | 1.755646929 | 1.755646929 | 46.28433 | 1.26E-05 | |
Residual | 13 | 0.493113071 | 0.037931775 | |||
Total | 14 | 2.24876 | ||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
Intercept | 0.72177665 | 0.3511329 | 2.055565429 | 0.060486 | -0.0368 | 1.480353161 |
Student ACT Score (Independent Variable) | 0.105545685 | 0.015513989 | 6.803259071 | 1.26E-05 | 0.07203 | 0.13906162 |
Solutionb:
1) indicate whether there is a significant relationship between students' ACT scores and their GPAs,
t statistic for slope=6.803
p=0.000013
p<0.05
Reject H0
Accept Ha.
at 5% level of significance there is a significant relationship between students' ACT scores and their GPAs.
Solution2:
GPA=0.7218+0.1055*ACT
slope=0.1055
y intercept=0.7218
d 3) use this prediction line to compute the predicted GPA with an ACT score of 20.
For ACT=20 substitute in regression eq
GPA=0.7218+0.1055*ACT
GPA=0.7218+0.1055*20
= 2.8318
predicted GPA=2.8318