During isobaric process m=64 kg of wet water stream at temperature t=262.7?C and pressure p=49 bar...

During isobaric process m=64 kg of wet water stream at temperature t=262.7?C and pressure p=49 bar changed its specific volume from v1 =0.0018 m3/kg to v2=0.035 m3/kg. Find initial and final quality of steam, change of internal energy of steam, work done by steam, amount of heat exchanged with surroundings. Draw the process at the enthalpy-entropy diagram. From tables for p=49 bar: v’=0.0013 m3/kg, v”=0.0403 m3/kg, h’= 1148.4 KJ/kg, h”= 2794.7 KJ/kg

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samet mamat answered 2 years ago

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