Question

Using Python 3

The primary objective of this assignment is to reinforce the concepts of string processing.

Part A: Even or Odd

For this first part, write a function that will generate a random number within some range (say, 1 to 50), then prompt the user to answer if the number is even or odd. The user will then input a response and a message will be printed indicated whether it was correct or not. This process should be repeated 5 times, using a new random number for each play, regardless of whether the user was correct or not.

Notes

• A correct response for an even number can be any of the following: “even”, “Even”, “EVEN”, “e”, “E”. “EiEiO”. The main criterion is that a correct response begins with the letter “e”, regardless of case. The same goes for an odd number – a correct response should begin with the letter “o”.
• If the user enters an invalid response, they should be notified. However, an invalid response still counts as one of the 5 plays.
• The solution should contain a loop (for or while) and a few if statements. An example execution is shown below:

>>> assign2PartA()
Is 41 odd or even? Odd
   Correct
Is 48 odd or even? Even
   Correct
Is 3 odd or even? e
   Incorrect
Is 20 odd or even? o
   Incorrect
Is 42 odd or even? xyz
   You did not enter a correct reply.
     Please answer using Odd or Even

Part B: Vowel Counting

The second task is to write a function that counts, and prints, the number of occurrences for each vowel (a, e, i, o and u) in a given phrase and outputs a (new) phrase with the vowels removed. The phrase should be accepted as a parameter to the function. If the (original) phrase is empty, you should output an appropriate error message, and obviously with no vowel counts. If the phrase contains no vowels, a message should be displayed, and the count can be omitted – since there is no point in displaying 0 for each vowel! A message should also be displayed if the phrase contains only vowels, but the counts should still be displayed.

Notes

• Recall that you can use the tab escape character (“\t”) for spacing to align the text, or use a given width in the f-string (print(f"{count_a:4}, ……”), where the value of count_a here is right justified in 4 columns.)
• Be sure to correctly handle both upper- and lower-case letters (e.g. both “a” and “A” should be counted as an instance of the letter “A”.) The new phrase (with vowels removed) should preserve the letter cases from the original phrase. Be sure to show output for all possible scenarios in your submitted output. A few example executions are shown below. In the first example, the escape sequence \" allows for inclusion of a " within a string delimited by two ", see slide 9 in “Working with Strings.”

>>> assign2PartB("Remember that context here defines \"+\" as 'Concatenate'")
   A    E    I    O    U
   4   10    1    2    0

The original phrase is: Remember that context here defines "+" as 'Concatenate'
The phrase without vowels is: Rmmbr tht cntxt hr dfns "+" s 'Cnctnt'

>>> assign2PartB("bcdfghjklmnpqrstvwxyz")

The phrase contains no vowels: bcdfghjklmnpqrstvwxyz

>>> assign2PartB("aeiouAEIOU")
   A    E    I    O    U
   2    2    2    2    2

The phrase contains only vowels: aeiouAEIOU

>>> assign2PartB("")

The input phrase is empty!

>>>

Answer 1

** Compiled in Spyder **

CODE:

import random

def assign2PartA():
    # Running a for loop for 5 iterations.
    for i in range(5):
        # Generating a random number between 1 and 50 using random.randint().
        num = random.randint(1, 50)
        # Creating a question by concatenating the random int and string.
        question = 'Is ' + str(num) + ' odd or even? '
        # Reading response from the user.
        response = input(question)
        # Converting the input to upper case, so that we can just check for capital letters.
        response = response.upper()
        # If the first letter is not 'E' or 'O', then it is an invalid input.
        if response[0] != 'E' and response[0] != 'O':
            print('  You did not enter a correct reply.\n   Please answer using Odd or Even')
        # If the random number generated is even and the response starts with 'E', 
        # then the answer is correct.
        elif num % 2 == 0 and response[0] == 'E':
            print('  Correct')
        # If the random number generated is odd and the response starts with 'O', 
        # then the answer is correct.
        elif num % 2 != 0 and response[0] == 'O':
            print('  Correct')
        # else the answer is incorrect.
        else:
            print('  Incorrect')

def assign2PartB(string):
    # Initializing a, e, i, o, u as 0.
    # To store the number of occurrence.
    a = e = i = o = u = 0
    
    # Traversing through the string letter by letter and incrementing the value of the variable
    # corresponding to vowels.
    for letter in string:
        if letter == 'A' or letter == 'a':
            a += 1
        elif letter == 'E' or letter == 'e':
            e += 1
        elif letter == 'I' or letter == 'i':
            i += 1
        elif letter == 'O' or letter == 'o':
            o += 1
        elif letter == 'U' or letter == 'u':
            u += 1
    # total -> total number of vowels present in the string.
    total = (a + e + i + o + u)
    
    # If the string is empty, print 'phrase is empty'.
    if string == "":
        print('The input phrase is empty!')
    # If there is no vowels, print 'no vowels'.
    elif total == 0:
        print('The phrase contains no vowels:', string)
    else:
        # else print the occurrences of each vowels.
        print('A \t E \t I \t O \t U')
        print(a, '\t', e, '\t', i, '\t', o, '\t', u)
        
        # If all the letters are vowels, print 'only vowels'.
        if len(string) == total:
            print('The phrase contains only vowels:', string)
        # else print the original string and another string wihtout vowels.
        else:
            print('The original phrase is:', string)
            # creating an empty string.
            new_string = ""
            # Appending all the consonant to new_string.
            for letter in string:
                if letter not in "aeiouAEIOU":
                    new_string += letter
            
            print('The phrase without vowels is:', new_string)

# calling assign2PartA()
assign2PartA()
print()

# calling assign2PartB() with different strings
string1 = "Remember that context here defines \"+\" as 'Concatenate'"
string2 = "bcdfghjklmnpqrstvwxyz"
string3 = "aeiouAEIOU"
string4 = ""

assign2PartB(string1)
print()
assign2PartB(string2)
print()
assign2PartB(string3)
print()
assign2PartB(string4)

Screenshots:

refer this to know the proper indentations.

Sample I/O:

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