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A 10.00 g mixture of NaHCO3 and Na2CO3 was heated and yielded 0.0274 moles H2O and...

A 10.00 g mixture of NaHCO3 and Na2CO3 was heated and yielded 0.0274 moles H2O and 0.106 moles CO2. Calculate the percent composition of the mixture.

2NaHCO3 → Na2O + 2CO2 + H2O

Na2CO3 → Na2O + CO2

What is the percent NaHCO3 of the mixture?

What is the percent Na2CO3 of the mixture?

Solutions

Expert Solution

Following is the Solution to the given question, in.... image format.........................

Since, we have Molar Mass of NaHCO3 = 84 g/mol ...and we know Moles of NaHCO3 (i.e. 'X' ) = 0.0548 moles

   and   Molar Mass of Na2CO3 = 106 g/mol ...and we know Moles of Na2CO3 (i.e. 'Y' ) = 0.0512 moles

Therefore.... we have:

   Mass of NaHCO3 = (84 g/mol) x (0.0548 mole) = 4.6 g (i.e. grams in 10 g Mixture ).... and...

..... Mass of Na2CO3 = (106 g/mol) x (0.0512 mole) = 5.427 g (i.e. grams in 10 g Mixture)

Therefore:

   % NaHCO3 = (4.6 g / 10.0 g ) x 100 = 46 % .....in Mixture

... % Na2CO3 = (5.4 g / 10.0 g ) x 100 = 54 % .....in Mixture

The above are the correct Answers to the given problem......


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