Question

which are true:

A) The 2nd ionization energy for k would be represented using the equation K+(g) --> K2+(g)+e-

B) the first ionization energy of Br should be smaller than the first ionization energy of Br2-

C) the successive ionization (in a hypothetical unit) for an unknown element are IE1=200, IE2=300, IE3=425, IE4=2500. The possible identity of the element is Be.

Answer 1

A) the second ionization of potassium is given by

K+ (g) ---> K+2 (g) X+ 2e-

so

the given statement is true

B)

Br2- ---> Br2 + e-

we know that

Br2 is a stable octet

so

the one electron excess can be removed easily to get the octet of Br2

now

Br ---> Br+ + e-

now

Br has 5 valence electrons

the outermost electron of Br can also be easily removed

but it is not as easy as that in Br2-

so

the given statement is false

C)

IE1 = 200

IE2 = 300

IE3 = 425

IE4 = 2500

we can see that

there is a huge jump between IE3 and IE4

so

after IE3 it has a stable electronic configuration

so

there are 3 valence electrons in the element

but

we know that

Be has only 2 valence electrons

the element cannot be Be

so

the given statement is false

finally

the true statement is A