The successive ionization energies of a certain third-period
element are I1 = 577.9KJ/mol, I2 + 1820 KJ/mol, I3 = 2750 KJ/mol,
I4 = 11600 KJ/mol, I5 = 14800 KJ/mol. what element do these
ionization energies suggest? Explain your reasoning.
The successive ionization energies for an unknown element are
IE1 = 896 kJ/mol IE2 =1752 kJ/mol IE3 =14,807 kJ/mol IE4 =17,948
kJ/mol To which family in the periodic table does the unknown
element most likely belong?
A certain main-group element exhibits the following successive
ionization energies in kJ/mol: IE1 = 100; IE2 = 300; IE3 = 700; IE4
= 3100; IE5 = 4200 Select the false statement about this element
below. 1) This element likely ionizes to form a cation when
participating in ionic compound formation. 2)The highest-energy
electron in an atom of this element resides in a p orbital. 3)This
element has four valence electrons. 4)This element is likely a
metallic element.
Identify the element of Period 2 that has the following
successive ionization energies, in kJ/mol.
IE1 = 1314 IE2 = 3389 IE3 =
5298 IE4 = 7471 IE5 = 10992 IE6 =
13329 IE7 = 71345 IE8 =
84087
Li
Ne
B
O
Determine which 3 element is being described by the following
successive ionization energies (kJ/mol)
Ei1 = 578; Ei2 = 1,817; Ei3 = 2,745; Ei4 = 11,575; Ei5 = 14,830;
Ei6 = 18,376; and Ei7 = 23,293?
Al
S
Cl
Mg
An element of the third period has the following ionization
energies in KJ/mol: IE1 = 1012, IE2 = 1903, IE3 = 2910, IE4 = 4956,
IE5 = 6278 and IE6 = 22,230. USing only this data determine which
one is the element.
The first four ionization energies in kJ/mol of a certain
second-row element are 801, 2427, 3660, and 25,025. What is the
likely identity of the element?
The ionization energy of a certain element is 352 kJ/mol.
(Ionization energy is the minimum energy required to remove an
electron from an atom. It is usually expressed in units of kJ/mol;
that is, it is the energy in kilojoules required to remove one mole
of electrons from one mole of atoms.) However, when the atoms of
this element are in the first excited state, the ionization energy
is only 166 kJ/mol. Based on this information, calculate the
wavelength of...
Question 1:
a. The first four ionization energies of an element are
approximately:
738 kJ mol-1, 1450 kJ mol-1, 7.7 x 103 kJ mol-1, and 1.1 x 104 kJ
mol-1.
Which family (group) of elements does this element belong?
Explain.
b. In a photoelectron spectroscopy experiment the kinetic energy
of the ejected electron from
a potassium atom is found to be 5.34 x 10-19 J using a UV source of
wavelength 162 nm.
Calculate the ionization energy.
i. It is...