Question

If the specific heat of a solution is 4.18 J/g^oC, and you have 206 mL (1.03 g/mL) which increases in temperature by 2.6 degrees, how many kilojoules did the solution absorb?

Answer 1

Specific Heat means 1 gm of substance absorb heat energy i.e 4.18.jouls/gm

V= 206 mL ,       d=1.03 g/mL   weight= denisityx Volume

                                                         =1.03x206

                                                           =212.18 gm..

1 gm of substance absorb heat energy    4.18.jouls/gm

212.18 gm.of substace absorb heat energy                ? (X)

                                                            X=4.18X212.18

                                                             =886.9 JOULS/gm

                                                             =886.9 x10^-3 kilojouls/gm