Question

In: Statistics and Probability

A recent study found that 63 children who watched a commercial for potato chips featuring a...

A recent study found that 63 children who watched a commercial for potato chips featuring a celebrity endorser ate a mean of 35 grams of potato chips as compared to a mean of 26 grams for 53 children who watched a commercial for an alternative food snack. Suppose that the sample standard deviation for the children who watched the​ celebrity-endorsed commercial was 21.4 grams and the sample standard deviation for the children who watched the alternative food snack commercial was 12.7 grams.

part a

Assuming that the population variances are equal and a= 0.05 s there evidence that the mean amount of potato chips eaten was significantly higher for the children who watched the​ celebrity-endorsed commercial?

Let population 1 be the weights of potato chips eaten by children who watched the​ celebrity-endorsed commercial and let population 2 be the weights of potato chips eaten by children who watched the alternative food snack commercial. What are the correct null and alternative​ hypotheses?

a- Ho: m1 -m2 not equal 0, H1: m1 - m2 =0

b- Ho: m1 - m2 less than or equal to 0, H1: m1-m2 >0

c- Ho : m1-m2 =0 , H1: m1 -m2 not equal to 0

d- Ho: m1- m2 greater than or equal to 0, H1: m1 -m2 < 0

what is the t statistic (round 2 decimal places)

what is the p value ( round 3 decimal places)

what is the correct conclusion

a- reject Ho; there is suffiecient evidence

b- do not reject ho: there is insuffiecient evidnce

c- do not reject ho: there is suffiecient evidence

d- reject Ho: there is insufficient evidence

part b -

assuming that the population variances are equal construct a 95% confidence interval estimate of the difference m1-m2 between the mean amount of potato chips eaten by the children who watched the celebrity endorsed commercial and children who watched the alternative food snack commercial.

blank is less than or equal to m1 - m2 is less than or equal to blank .

part c -

compare and discuss the results of a and b

a- the confidence interval in part b contains 0, which does not agree with the decision made in part a to reject the null hypothesis

b- the confidence interval in part b does not contain 0, which does not agree with the decision made in part a to not reject the null hypothesis

c- the confidence interval in part b contains 0 , which agrees with the decision made in part a to not reject the null hypothesis

d- the confidence interval in part b does not contain 0, which agrees with the decision made in part a to reject the null hypothesis

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