Question

C++ Write a toVector function that takes in a C-style pointer of any type and a size (int) and returns a vector of the same size containing a copy of the elements in the input array. You may assume that the array elements have a valid copy constructor. Please explain every line of code to me

Answer 1

Code:

#include<iostream>
#include<vector>
using namespace std;

//function toVector definition.
//Since the array is int array the return type should be vector<int>
vector<int> toVector( int *arr, int n)
{
    //declare a new int vector xvec
    vector<int> xvec;
    //using for loop from 0 to n
    for(int i=0; i<n; i++)
    {
        //add elements of array to xvec vector using push_back()
        xvec.push_back(*arr);
        //increment the var1++ so that it goes to next address of elements
        arr++;
    }
    //return xvec
    return(xvec);
}

int main()
{
    //initialize an array
     int arr[] = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100};
     int n = sizeof(arr)/sizeof(arr[0]);
     //store the returned vector from function in another vector res
     vector<int> res= toVector(arr, n);
     //using for loop display the vector elements
     cout << "The elements of vector are:\n";
     for(int i = 0; i< n;i++)
     cout << res[i] <<"\n";
     return 0;
}

O/P:

The elements of vector are:
10
20
30
40
50
60
70
80
90
100

Code screenshot:

O/P screenshot: