Question

In: Physics

After studying alternating current waveforms, half-wave rectification and capacitor smoothing, a student proposes the following hypothesis:...

After studying alternating current waveforms, half-wave rectification and capacitor smoothing, a student proposes the following hypothesis:
The peak-to-peak value of the ripple voltage obtained with a capacitor smoothed, half-rectified sinusoidal waveform is proportional to the logarithm (base 10) of the value of the smoothing capacitor used.
Design an experiment to verify the hypothesis above

Solutions

Expert Solution

As proposed by the student the rectifier was designed with a capacitor filter

At the point when AC voltage is connected, amid the positive half cycle, the diode D is forward biased and permits electric current through it.

As we definitely realize that, the capacitor gives high resistive path to dc components (low-frequency signal) and low resistive path to ac components (high-frequency signal).

Electric current dependably likes to course through a low resistance path. So when the electric current achieves the filter, the dc components experience a high resistance from the capacitor and ac components experience a low resistance from the capacitor.

The dc parts dislikes to move through the capacitor (high resistance path). So they locate an elective way (low resistance path) and streams to the load resistor (RL) through that path.

As said the peak to peak value of the ripple voltage obtained with a capacitor is smoothed and half-rectified sinusoidal waveform is proportional to the logarithm (base 10) of the value of the smoothing capacitor used by below eqution

where is frequency of the wave


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