In: Physics
Data Tables
Part 1
Figure 1.2
Capacity Meter Measurements
Diameter of plates: 176 MM
Area of plates: 24328.49351MM2
Distance (MM) |
Capacitance (NF) |
2 |
00.30 |
5 |
00.25 |
8 |
00.23 |
10 |
00.22 |
15 |
00.21 |
20 |
00.20 |
30 |
00.19 |
Figure 1.3
Capacity Meter with Lucite Measurements
Lucite thickness: 1.871MM
Distance (MM) |
Capacitance (NF) |
2 |
00.46 |
30 |
00.19 |
Figure 1.4
Capacity Meter with Cardboard
Cardboard thickness: 3.802 MM
Distance (MM) |
Capacitance (NF) |
4 |
00.30 |
30 |
00.19 |
Part 2
Figure 1.5
Copper Lucite Capacity Meter
Copper plate dimensions: 255˟101MM
Distance between Copper plates: 0.1MM
Distance (MM) |
Area (MM2) |
Capacitance (NF) |
255 |
25755 |
1.2 |
200 |
20200 |
1.02 |
150 |
15150 |
00.76 |
100 |
10100 |
00.57 |
50 |
5050 |
00.37 |
20 |
2020 |
00.28 |
Qualitatively how do the dielectric constants of lucite and the other materials compare to those of air? Calculate the dielectric constant for lucite and cardboard using the value of capacitance using the value of capacitance you obtained when the plates were as close to the dielectric as possible.
I have no idea where to start please help.
First of all you have not mentioned which table has the readings for air filled capacitor. I am assuming it to be first one i guess. The lucite material has the highest dielectric constant amongst the given materials especially higher than air and cardboard.
In order to find the dielectric constant you need to remember the relationship between capacitance and dielectric constant. For example
For the case of air K ~ 1. Therefore, absolute capacitance or capacitance with air as dielectric constant is
Simply, put in the value of capacitance for the case of air and the material for value of area of plates and separation.