Question

In: Physics

Data Tables Part 1 Figure 1.2 Capacity Meter Measurements Diameter of plates: 176 MM Area of...

Data Tables

Part 1

Figure 1.2

Capacity Meter Measurements

Diameter of plates: 176 MM

Area of plates: 24328.49351MM2

Distance (MM)

Capacitance (NF)

2

00.30

5

00.25

8

00.23

10

00.22

15

00.21

20

00.20

30

00.19

Figure 1.3

Capacity Meter with Lucite Measurements

Lucite thickness: 1.871MM

Distance (MM)

Capacitance (NF)

2

00.46

30

00.19

Figure 1.4

Capacity Meter with Cardboard

Cardboard thickness: 3.802 MM

Distance (MM)

Capacitance (NF)

4

00.30

30

00.19

Part 2

Figure 1.5

Copper Lucite Capacity Meter

Copper plate dimensions: 255˟101MM

Distance between Copper plates: 0.1MM

Distance (MM)

Area (MM2)

Capacitance (NF)

255

25755

1.2

200

20200

1.02

150

15150

00.76

100

10100

00.57

50

5050

00.37

20

2020

00.28

Qualitatively how do the dielectric constants of lucite and the other materials compare to those of air? Calculate the dielectric constant for lucite and cardboard using the value of capacitance using the value of capacitance you obtained when the plates were as close to the dielectric as possible.

I have no idea where to start please help.

Solutions

Expert Solution

First of all you have not mentioned which table has the readings for air filled capacitor. I am assuming it to be first one i guess. The lucite material has the highest dielectric constant amongst the given materials especially higher than air and cardboard.

In order to find the dielectric constant you need to remember the relationship between capacitance and dielectric constant. For example

For the case of air K ~ 1. Therefore, absolute capacitance or capacitance with air as dielectric constant is

Simply, put in the value of capacitance for the case of air and the material for value of area of plates and separation.


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