In: Statistics and Probability
Forty-eight participants were randomly assigned to do math tasks
under one of three conditions: 16 while listening to soft gentle
music, 16 while listening to loud intense music, and 16 while in
silence. The means and estimated population variances for the three
groups were: Soft-gentle: M = 33, S2 =
25; Loud-intense: M = 42, S2 = 36;
Silence M = 42, S2 = 16.
Do these results suggest that there is a difference in performance
on this kind of math task under these three conditions? (Use the
.05 level.)
Choose the appropriate test and use the five steps of hypothesis testing.
A | B | C | ||||
count, ni = | 16 | 16 | 16 | |||
mean , x̅ i = | 33.000 | 42.00 | 42.00 | |||
std. dev., si = | 25.000 | 36.000 | 16.000 | |||
sample variances, si^2 = | 625.000 | 1296.000 | 256.000 | |||
total sum | 528 | 672 | 672 | 1872 | (grand sum) | |
grand mean , x̅̅ = | Σni*x̅i/Σni = | 39.00 | ||||
square of deviation of sample mean from grand mean,( x̅ - x̅̅)² | 36.000 | 9.000 | 9.000 | |||
TOTAL | ||||||
SS(between)= SSB = Σn( x̅ - x̅̅)² = | 576.000 | 144.000 | 144.000 | 864 | ||
SS(within ) = SSW = Σ(n-1)s² = | 9375.000 | 19440.000 | 3840.000 | 32655.00 |
no. of treatment , k = 3
df between = k-1 = 2
N = Σn = 48
df within = N-k = 45
mean square between groups , MSB = SSB/k-1 =
432.0000
mean square within groups , MSW = SSW/N-k =
725.6667
F-stat = MSB/MSW = 0.5953
anova table | ||||||
SS | df | MS | F | p-value | F-critical | |
Between: | 864.00 | 2 | 432.00 | 0.60 | 0.5557 | 3.20 |
Within: | 32655.00 | 45 | 725.67 | |||
Total: | 33519.00 | 47 |
α = 0.05
conclusion : p-value>α , do not reject null
hypothesis
there is NOT a difference in performance on this kind of
math task under these three conditions
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