In: Chemistry
Consider the effect of ionic strength, find the concentrations of Ag+, CN-, and HCN in a saturated solution of AgCN whose pH is fixed at 9.00 (consider the effect of ionic strength and activities. use a method of successive approximations, until your answers from two iterations agree to within 5%).
Equilibria:
AgCN (s) <---> Ag+ + CN- Ksp= 2.2 x 10-16
CN- + H2O <---> HCN + OH- Kb= 1.6 x 10-5
AgCN(s) [Ag+(aq)][CN-(aq)]
The silver and cyanide ion concentration formed is considered as 'x'.applying solubility product,
Ksp=x2
2.2*10^-16 =x2
X=√2.2*10^-16
=1.48*10^-8 moldm-3
[Ag+]=[CN-]=1.48*10^-8moldm-3
Since pH =9,solution is basic so Kb be applied.
Kb=[HCN][OH-]/[CN-]
Concentration of water is a constant=1
From ph ,[OH-] can be found.
[H+][OH-]=10^14
[OH-]=1*10^5 moldm-3
(1.6*10^-5×1.48*10^-8)/1*10^-5=[HCN]
[HCN]=2.368*10^-8 moldm-3