You wish to titrate a 0.147 M solution of HCN (pKa = 9.26) with a 0.163...

You wish to titrate a 0.147 M solution of HCN (pKa = 9.26) with a 0.163 M solution of NaOH. Ultimately, you add 117.4 mL of the NaOH solution to the 47.4 mL of HCN solution. What is the pH of the resulting solution?

Expert Solution

Titration

moles of HCN = 0.147 M x 47.4 ml

= 6.9678 mmol

moles of NaOH = 0.163 M x 117.4 ml

= 19.1362 mmol

excess NaOH = 12.1684 mmol/164,8 ml

= 0.074 M

pOH = -log[OH-]

= 1.132

pH = 14 - pOH = 12.868

queen_honey_blossom answered 2 years ago

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