In: Statistics and Probability
A)
As part of a larger project to study the behavior of stressed-skin panels, a structural component being used extensively in North America, an article reported on various mechanical properties of Scotch pine lumber specimens. Data on the modulus of elasticity (MPa) obtained 1 minute after loading in a certain configuration and 4 weeks after loading for the same lumber specimens is presented here.
Observation | 1 min | 4 weeks | Difference |
---|---|---|---|
1 | 10,490 | 9,160 | 1330 |
2 | 16,620 | 13,250 | 3370 |
3 | 17,100 | 14,720 | 2380 |
4 | 15,480 | 12,750 | 2730 |
5 | 12,960 | 10,120 | 2840 |
6 | 17,260 | 14,570 | 2690 |
7 | 13,400 | 11,220 | 2180 |
8 | 13,900 | 11,100 | 2800 |
9 | 13,630 | 11,420 | 2210 |
10 | 13,240 | 10,930 | 2310 |
11 | 14,370 | 12,110 | 2260 |
12 | 11,700 | 8,620 | 3080 |
13 | 15,470 | 12,590 | 2880 |
14 | 17,840 | 15,090 | 2750 |
15 | 14,070 | 10,550 | 3520 |
16 | 14,760 | 12,230 | 2530 |
Calculate an upper confidence bound for the true average
difference between 1-minute modulus and 4-week modulus; first check
the plausibility of any necessary assumptions. (Use α =
0.05. Round your answer to two decimal places.)
MPa=_______
B)
It is thought that the front cover and the nature of the first question on mail surveys influence the response rate. An article tested this theory by experimenting with different cover designs. One cover was plain; the other used a picture of a skydiver. The researchers speculated that the return rate would be lower for the plain cover.
Cover | Number Sent | Number Returned |
---|---|---|
Plain | 207 | 102 |
Skydiver | 214 | 109 |
Does this data support the researchers' hypothesis? Test the relevant hypotheses using α = 0.10 by first calculating a P-value.
Compute the test statistic value and find the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.)
z = | |
P-value = |
C)
Do teachers find their work rewarding and satisfying? An article reports the results of a survey of 396 elementary school teachers and 261 high school teachers. Of the elementary school teachers, 224 said they were very satisfied with their jobs, whereas 125 of the high school teachers were very satisfied with their work. Estimate the difference between the proportion of all elementary school teachers who are satisfied and all high school teachers who are satisfied by calculating a 95% CI. (Use pelementary − phigh school. Round your answers to four decimal places.)
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Ans A ) using minitab>stat>basic stat>Paired t
we have
Paired T-Test and CI: 1 min, 4 weeks
Paired T for 1 min - 4 weeks
N Mean StDev SE Mean
1 min 16 14518 2040 510
4 weeks 16 11902 1897 474
Difference 16 2616 522 130
95% upper bound for mean difference: 2844.91
T-Test of mean difference = 0 (vs < 0): T-Value = 20.06 P-Value
= 1.000
an upper confidence bound for the true average difference between 1-minute modulus and 4-week modulus is 2844.91
Ans B ) using excel>addin>phstat>two sample test
we have
Z Test for Differences in Two Proportions | |
Data | |
Hypothesized Difference | 0 |
Level of Significance | 0.1 |
Group 1 | |
Number of Items of Interest | 102 |
Sample Size | 207 |
Group 2 | |
Number of Items of Interest | 109 |
Sample Size | 214 |
Intermediate Calculations | |
Group 1 Proportion | 0.492753623 |
Group 2 Proportion | 0.509345794 |
Difference in Two Proportions | -0.01659217 |
Average Proportion | 0.5012 |
Z Test Statistic | -0.3404 |
Lower-Tail Test | |
Lower Critical Value | -1.2816 |
p-Value | 0.3668 |
Do not reject the null hypothesis |
z =-0.34 | |
P-value =0.3668 |
C) using excel>addin>phstat >2 sample test
\we have
Z Test for Differences in Two Proportions | ||||
Data | Confidence Interval Estimate | |||
Hypothesized Difference | 0 | of the Difference Between Two Proportions | ||
Level of Significance | 0.05 | |||
Group 1 | Data | |||
Number of Items of Interest | 224 | Confidence Level | 95% | |
Sample Size | 396 | |||
Group 2 | Intermediate Calculations | |||
Number of Items of Interest | 125 | Z Value | -1.9600 | |
Sample Size | 261 | Std. Error of the Diff. between two Proportions | 0.0397 | |
Interval Half Width | 0.0778 | |||
Intermediate Calculations | ||||
Group 1 Proportion | 0.565656566 | Confidence Interval | ||
Group 2 Proportion | 0.478927203 | Interval Lower Limit | 0.0089 | |
Difference in Two Proportions | 0.086729363 | Interval Upper Limit | 0.1646 | |
Average Proportion | 0.5312 | |||
Z Test Statistic | 2.1799 | |||
Two-Tail Test | ||||
Lower Critical Value | -1.9600 | |||
Upper Critical Value | 1.9600 | |||
p-Value | 0.0293 |
95% confidence interval is ( 0.0089 ,0.1646)