Mendelian genetics predict that in Labrador retrievers (a type of dog), 25% should have brown coat...

Mendelian genetics predict that in Labrador retrievers (a type of dog), 25% should have brown coat color if both parents are heterozygous (the rest are black). You mate two parents and get a litter of 8 puppies. Calculate the following:

a) The probability of 6 black puppies.

b) The probability of 3 brown puppies.

c) The probability that 50% of the puppies will be brown.

(Comment: You do not need to know anything about genetics to solve this problem. If you're trying to do things like use punnet squares, you're doing things wrong)

Expert Solution

orchestra answered 1 year ago

Labrador retrievers are black, brown, or yellow. In a cross of a black female with a...

Labrador retrievers are black, brown, or yellow. In a cross of a black female with a brown male, results can be all black puppies, 1/2 black to 1/2 brown puppies, or 3/4 black to 1/4 yellow puppies. What is/are the genotype(s) that results in the black phenotype, brown phenotype, and yellow phenotype?

In Labrador retrievers coat color is controlled by two independently assorting loci. The B locus controls...

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Labrador retriever dogs have three coat colors: black, brown and yellow. The color of the pigment...

Labrador retriever dogs have three coat colors: black, brown and yellow. The color of the pigment deposited in the hairs is determined by a gene with two alleles (B or b). The B allele codes for black pigment and is dominant to the b allele which codes for brown. Another gene with two alleles (E or e) determines if the pigment created will be deposited into the hairs. If both copies (ee) are recessive, no pigment will be deposited (regardless...

In Labrador retrievers, there are 3 gene products involved in determining coat color: gene product B, gene...

In Labrador retrievers, there are 3 gene products involved in determining coat color: gene product B, gene product E, and gene product C. B produces a melanin pigment such that B/B and B/b will produce a black lab while b/b (with less melanin produced) will result in a chocolate lab. However, for the B gene to be expressed, a signaling hormone (gene E product) must be produced to activate transcription of the B gene. E is fully dominant to e (loss of function mutation). In...

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