Question

In: Physics

Data: Part A: Testing Archimedes’ Law W (g) Wapp, W (g) Wb,i (g) Wb,f (g) 40.6...

Data:

Part A: Testing Archimedes’ Law

W (g)

Wapp, W (g)

Wb,i (g)

Wb,f (g)

40.6 g

29.3 g

104.6 g

123.2 g

Part B: Calculating the density of a solid object and ethanol

W (g)

Wapp, W (g)

Wapp, E

40.6 g

29.3 g

29.9 g

Part C: Calculating the density of a floating object

Ltotal (cm)

W (cm)

H (cm)

m (g)

Lsub (cm)

30.48 cm

2.794 cm

3.302 cm

197.9 g

21.844 cm

CALCULATION AND ANALYSIS

1. Calculate the weight of the water displaced by the immersed object, Wb,f?Wb,i, using the data from Part A.

2. Calculate the apparent loss of weight of the object when completely immersed in water, W?Wapp,W, using the data from Part A.

3. Archimedes' Law predicts that the weight of the displaced water equals the apparent loss of weight of the object. Do your results support Archimedes' Law?

4. Calculate the density of the object ?obj using equation 8.7 and the data from Part B.

5. Calculate the % error in your result for ?obj.

6. Calculate the density of the ethanol ?E using equation 8.8 and the data from Part B.

7. Calculate the % error in your result for ?E.

8. Calculate the density of the wooden dowel ?wood, float using equation 8.10 and the data from Part C.

9. Calculate the volume of the wooden dowel using your data from Part C. (Remember for a cube volume = length × width × height.)

10. Calculate the actual density of the wood block pwood,actual= m/volume using your data from Part C.

11. Using ?wood, actual as the accepted value, calculate the % error in your result for ?wood, float.

Solutions

Expert Solution

?1. The weight of the water displaced by the immersed object:

2. The apparent loss of weight of the object when completely immersed in water:

3.Archimedes' Law predicts that the weight of the displaced water equals the apparent loss of weight of the object. No, above result does not support this.

4. The density of the object :

5. The % error :

Density of floating object :

% error = (20.15 - 3.539)/20.15 * 100 =82 %


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