Question

In: Statistics and Probability

A company applies an aptitude test to all those who apply for jobs as programmers. The...

A company applies an aptitude test to all those who apply for jobs as programmers. The results of these tests are analyzed according to their precedence (general advertising, ads in specialized magazines, employment agencies, personal recommendations or people who come spontaneously). With a significance level of 0.025, determine if there is a difference between the results of these tests according to their precedence. Your work should have detailed procedure, in this exercise you can use the tool offered by Excel for the required test, but you have to have the appropriate analysis.

General Pub 36 47 38 51 62 78 60 47 49 53 26 38 61 39 43
Rev Esp. 58 64 62 47 71 90 65 82 61 59
Ag Emp. 47 59 48 81 66 50 42 53
Rec Per. 67 61 82 97 65 72 54 59 58
Spontaneous 38 47 80 41 38 66 50

Solutions

Expert Solution

The hypotheses will be

H0: all the precedence is equal .i.e. there is no significant difference between the precedence

H1: At least two of the precedence is not equal i.e. there is a significant difference between the precedence

The appropriate analysis that can be used is ANOVA for a single factor. We can conduct this test using MS Excel.

Enter data Data Data Analysis Anova: Single Factor

Provide the necessary details and make α=0.025 them the following appears.

Anova: Single Factor

SUMMARY

Groups

Count

Sum

Average

Variance

General Pub.

15

728

48.53333

169.6952

Rev Esp.

10

659

65.9

152.9889

Ag Emp.

8

446

55.75

159.9286

Rec Per.

9

615

68.33333

186

Spontaneous

7

360

51.42857

253.2857

ANOVA

Source of Variation

SS

df

MS

F

P-value

F crit

Between Groups

3248.561

4

812.1401

4.53488

0.003736

3.093288

Within Groups

7879.848

44

179.0874

Total

11128.41

48

The critical value of F for (4, 44) d.f and α=0.025 level of significance is 3.093288.

Since the calculated value is greater than critical value and the p-value is less than 0.025, we reject the null hypothesis and conclude that with 97.5% confidence that the precedence differ significantly. So thers is a difference between the results of these tests according to their precedence.

I request you to provide a feedback regarding the answer.


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