3.A black guinea pig (Bb) is crossed with an albino guinea pig (bb). Note: Black is...

3.A black guinea pig (Bb) is crossed with an albino guinea pig (bb). Note: Black is dominant over albino. Use a Punnett square to determine the genotypes and phenotypes of the parents and offspring.

4. Note: the genotype of females is XX; for males is XY. Use a Punnett square to determine the genotypes and phenotypes of the offspring. a. If a couple has 3 girls, what are possibilities of the 4th child to be another girl?

5. A father with blue eyes (bb) is married to a woman with hazel eyes (Bb). Use a Punnett square to determine the genotypes and phenotypes of the offspring

Solutions

Expert Solution

3. If black is dominant over albino then,

genotype of parents will be Bb and bb and phenotype will be Black and albino respectively.

Genotypes of offsprings as Bb, Bb, bb and bb. Phentypes as Black, black and albino and albino respectively.

4. If three children are already daughters that doesn't affect the gender of fourth child. There are 50% chances of the child being a girl or a boy as usual.

Genotype will be as XX, XX XY and XY. Phentypes as female, female, male and male respectively.

5. Genotype of offsprings : Bb, bb, Bb and bb.

Phentypes :Hazel eyed F, blue eyed F, hazel eyed M and blue eyed male respectively.

gladiator answered 1 year ago

Next > < Previous

Related Solutions

1)A black guinea pig crossed with an albino guinea pig produced twelve black offspring. When the...

1)A black guinea pig crossed with an albino guinea pig produced twelve black offspring. When the albino was crossed with a second black guinea pig, six blacks and six albinos were obtained. What is the best explanation for this genetic situation? A)Albino is recessive; and the second black guinea pig was homozygous dominant B)Albino is co-dominant; and the second black guinea pig was heterozygous C)Albino is recessive; and the second black guinea pig was heterozygous D)Albino and black are codominant....

Your high school crush is working with a breed of guinea pig in which the side...

Your high school crush is working with a breed of guinea pig in which the side on which the hair parts down the back is inherited, and it can either be on the left or the right. Left-parting appears to be dominant in this system. S/he/they crosses true-breeding parents that are phenotypically left-parters and gets a generation of right-parters. Inbreeding the F1 produces a generation that consists entirely of left-parters. f. How is this trait transmitted? g. What are the...

A researcher has three strains of mice: black, brown, and albino. She crosses the true-breeding albino...

A researcher has three strains of mice: black, brown, and albino. She crosses the true-breeding albino mice with the true-breeding black mice and finds that the F1 progeny are all brown. She then crosses the F1 generation with each other, producing 17 brown mice, 7 black mice and 8 albino mice in the F2 generation. Based on this observation, what is the most consistent mode(s) of inheritance would you propose to explain this results? A. Double recessive epistasis B. Recessive...

Java Code: Problem #1: Create an inheritance hierarchy of Rodent: mouse, gerbil, hamster, guinea pig. In...

Java Code: Problem #1: Create an inheritance hierarchy of Rodent: mouse, gerbil, hamster, guinea pig. In the base class, provide methods that are common to all rodents based on behaviours you find with a quick Internet search. Be sure to document the behaviours you implement (e.g., eat, sleep, groom, move, etc.). Each behaviour should print its action to standard output (e.g., rodent eating). Next, refine these behaviours in the child classes to perform different behaviours, depending on the specific type...

In a population of rats, the homozygous genotype BB produces black coat color, Bb produces gray...

In a population of rats, the homozygous genotype BB produces black coat color, Bb produces gray coat color, and bb produces white coat color. When the population is surveyed, you find that there are 60 black rats and 40 gray rats, and no rats with white coats. A. What are the gene frequencies for the B and b alleles in this population? B. If this rat population randomly mates, what are the expected ratios of black, gray, and white rats...

A black haired mouse was crossed to a hairless mouse. Since it lacked hair, it was...

A black haired mouse was crossed to a hairless mouse. Since it lacked hair, it was impossible to tell if its hair was black or brown. All the F1 progeny had black hair. When these F1 progeny were mated among themselves (to obtain the F2 generation), 96 were black, 43 were hairless, and 30 were brown (a) What is the approximate observed phenotypic ratio of these offspring? (1 points) (b) Explain the pattern of inheritance observed here (what are the...

Among guinea pigs, black hair is dominant over white hair. What would be the appearance of...

Among guinea pigs, black hair is dominant over white hair. What would be the appearance of the guinea pigs if a homozygous white hair male were mated with a homozygous white hair female? Dominant allele: ____ Recessive allele: ____ Genotypes of offspring: ___________________ Genotypes of parents: _________ Phenotypes of parents: _________ Phenotypes of offspring: ___________________ Among corn, long ears are dominant over short ears. What would be the appearance of the corn if two heterozygous long eared corn plants were...

In guinea pigs, white coat (w) is recessive to black coat (W) and wavy hair (v)...

In guinea pigs, white coat (w) is recessive to black coat (W) and wavy hair (v) is recessive to straight hair (V). A breeder crosses a guinea pig that is homozygous for white coat and wavy hair with a guinea pig that is black with straight hair. The F1 are then crossed with guinea pigs having white coats and wavy hair in a series of testcrosses. The following progeny are produced from these testcrosses: black, straight 30 black, wavy 10...

IN C++ Note: While there are many ways to do conversions to pig latin, I will...

IN C++ Note: While there are many ways to do conversions to pig latin, I will require that you follow the procedures below, all of which will use the following structure: struct Word { string english; string piglatin; }; Part 1. Write a function that takes in an English sentence as one string. This function should first calculate how many “words” are in the sentence (words being substrings separated by whitespace). It should then allocate a dynamic array of size...

what are at least 3 anatomical regions of a fetal pig

Subjects